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Which Calculus Textbook? |
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| Sep3-12, 12:14 PM | #1 |
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Which Calculus Textbook?
Hello, I need help with deciding which textbook to buy. All I want is your non-biased opinions on which is the better introduction Calculus book.
Calculus by Ron Larson Calculus, Vol. 1: One-Variable Calculus, with an Introduction to Linear Algebra by Tom M. Apostol Calculus: An Intuitive and Physical Approach by Morris Kline Calculus by Michael Spivak These are my options, what are your thoughts? |
| Sep3-12, 12:30 PM | #2 |
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Some of the choices you listed have very different target audiences, e.g. Spivak is almost a real analysis text, while Kline takes, as the title indicates, "an intuitive and physical approach". Give us some more detail about what kind of book you are looking for if you want a good recommendation.
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| Sep3-12, 12:37 PM | #3 |
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| Sep3-12, 02:20 PM | #4 |
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Which Calculus Textbook?
The best calculus book in my opinion is Spivak. It has really good explanations and many challenging (but hard) exercises.
The only problem with Spivak is that you're likely not ready for it. In order to read Spivak, you need to be familiar with calculus and proofs. So it's more like a second text on calculus. The same is true for Apostol. If you're encountering calculus for the first time, then you should check out "A first course in calculus" by Serge Lang. I liked that book very much and it's not as hard as Spivak (although that means it is less rigorous). Another book that should be good is "Quick Calculus" by Kleppner and Ramsey. You should check these two books out!! |
| Sep4-12, 04:28 PM | #5 |
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| Sep4-12, 04:37 PM | #6 |
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| Sep4-12, 05:14 PM | #7 |
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| Sep4-12, 05:33 PM | #8 |
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If x and y are not both zero, then [itex]x^2+xy+y^2>0[/itex]. Show this. For which numbers [itex]\alpha[/itex] is it true that [itex]x^2+\alpha xy+y^2>0[/itex] whenever x and y are both nonzero? If you can do things like that, then Spivak might be ok for you. |
| Sep4-12, 05:36 PM | #9 |
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Another one:
Let A be a subset of [itex]\mathbb{R}[/itex]. We call x an upper bound of A if [itex]x\geq a[/itex] for all a in A. The least upper bound of A is called the supremum of A. That is, if x is the supremum of A, then x is an upper bound and if y is another upper bound then [itex]x\leq y[/itex]. Now, assume that x is an upper bound of A. Show x is the supremum of A if and only if for each [itex]\varepsilon >0[/itex], there exists an a in A such that [itex]x-\varepsilon< a[/itex]. This is a pretty standard result that you should be able to prove yourself. |
| Sep4-12, 06:55 PM | #10 |
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