| New Reply |
Laplace Transform inversion |
Share Thread | Thread Tools |
| Sep14-12, 10:31 AM | #1 |
|
|
Laplace Transform inversion
I'm inverting this:
Y = s2 + 15s + 17 / [(s+1)(s2 + 13s - 4)] I'm using PF expansion, A/(s+1) + Bs + C/(s2 + 13s - 4), I however keep on getting wrong answers, seeing how Runge-Kutta and Taylor approximation disagrees with my final equation. My final equation is: exp(-13/2t)[19/16cosh√(185)/2t + 13√(185)/74sinh√(185)/2t] - 3/16exp(-t) = y, and it's wrong (considering Runge-Kutta and Taylor approximation disagrees with it). Obviously, something's wrong. What did I miss? I'm starting to think that the second term is.. well, there's something wrong with it (Bs + C term). I mean, the numerator is a quadratic, therefore it can't be that simple... NOTE: This is NOT homework. I did this to merely tickle my head. The original differential equation is y"+13y'-4y = 3exp(-t), y(0) = y'(0) = 1. |
| New Reply |
| Thread Tools | |
Similar Threads for: Laplace Transform inversion
|
||||
| Thread | Forum | Replies | ||
| Laplace inversion | Calculus | 1 | ||
| IVP Laplace Transform Problem -- Tricky Inverse Laplace Transform | Calculus & Beyond Homework | 5 | ||
| Laplace Inversion | Differential Equations | 6 | ||
| Laplace Transform inversion | Differential Equations | 8 | ||
| Inverse laplace transform with complex inversion theorm | Calculus & Beyond Homework | 0 | ||