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Problem: Multiples of pi |
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| Sep16-12, 05:26 PM | #1 |
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Problem: Multiples of pi
Hi everyone,
About 15 minutes ago I came up with a problem... What whole number multiple of pi would result in a number closest to a whole number? Does a single whole number multiple exist, and can we... prove it? Thanks for help in advance! -Daniel |
| Sep16-12, 05:41 PM | #2 |
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The number [itex]\pi[/itex] is not special here, it works for any irrational number. |
| Sep16-12, 06:42 PM | #3 |
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Ah, well there goes my bedtime tonight! Thanks for the direction :D |
| Sep25-12, 08:31 AM | #4 |
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Problem: Multiples of piHowever, here is how you would find such integers for pi. We know the close approximation of 22/7 for pi. Then we have: 22/7≈pi 22≈7pi And verifying, we have 7*pi≈21.99114858 Another close approximation is 333/106: 333/106≈pi 333≈106pi and 106pi≈333.0088213... I hope this proves useful! |
| Oct3-12, 01:52 PM | #5 |
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You might also be interested in the following thread from the wu riddle site;
"Say I am given a number X = A*[sqrt]2 + B*[pi], where A and B are integers. Given X, how can you find A and B, without using brute force?" It comes with a long discussion. see http://www.ocf.berkeley.edu/~wwu/cgi-bin/yabb/YaBB.cgi |
| Oct8-12, 12:37 PM | #6 |
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I ran a quick computer program just for interest sake.
78256779 103767361 129277943 131002976 156513558 180299107 182024140 183749173 205809689 207534722 209259755 233045304 234770337 236495370 258555886 260280919 262005952 Those numbers if multiplied with pi will give you a number so close to a integer that the decimal part can't fit in a double precision floating point. As stated above you can't actually get a integer from multiplying a integer with pi (except 0) |
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| brown university, multiple, number theory, whole number |
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