# Impedance of Parallel Circuit

by NullSpace0
Tags: circuit, impedance, parallel
 Homework Sci Advisor HW Helper Thanks P: 12,870 You have a complex admittance. The complex impedance is the reciprocal of the complex admittance "Impedence" and "complex impedance" can be used interchangeably: you'll have to use the context of your classes to decide if the modulus is expected or not (that's how I'd interpret it.) note; if ##y=a+jb## then, using ##|z|=|1/y|## (i.e. reciprocal then modulus):$$z=1/y = 1/(a+jb) = (a-jb)/(a^2-b^2)\Rightarrow |z| = \sqrt{a^2+b^2}/(a^2-b^2)$$... something like that - what happens if you do it in the other order (i.e. modulus then reciprocal). Is ##|1/y|=1/|y|##)? See: http://en.wikipedia.org/wiki/Electrical_impedance