# Wrote general equation for a free body diagram

by Vodkacannon
Tags: body, diagram, equation, free, wrote
 P: 39 So I derived this equation for the net force/acceleration of a motorcycle on a flat surface. I beleive this equation could practically be used for any rolling object. ƩF = Fp - μ*Fn - FD Where: FP is the force of the bike acting against the ground, tangent to the ground FD = $\frac{1}{2}$pv2CDA (air drag) μ*Fn is the frictional force of the tires, Fn is the normal force. Now to find a: ma = Fp - μFn - FD a = (Fp - μFn - FD) / m Is there anything wrong with this?
Homework
 ... for the net force/acceleration of a motorcycle on a flat surface. I beleive this equation could practically be used for any rolling object. ƩF = Fp - μ*Fn - FD Where: FP is the force of the bike acting against the ground, tangent to the ground FD = $\frac{1}{2}$pv2CDA (air drag) μ*Fn is the frictional force of the tires, Fn is the normal force. Now to find a: ma = Fp - μFn - FD a = (Fp - μFn - FD) / m Is there anything wrong with this?