## Polarized light; maximum number of disagreements?

Starting with 2 vertical photons, how can we argue that the maximum number of disagreements and minimum number for +30° and -30° is Nmin(-30°,30°) ≤ N(60°,0°) ≤ Nmax(-30°,30°)? and should we also not rotate the light?
 PhysOrg.com science news on PhysOrg.com >> Ants and carnivorous plants conspire for mutualistic feeding>> Forecast for Titan: Wild weather could be ahead>> Researchers stitch defects into the world's thinnest semiconductor
 Mentor What are you talking about?

Recognitions:
Gold Member
 Quote by xb4byish Starting with 2 vertical photons, how can we argue that the maximum number of disagreements and minimum number for +30° and -30° is Nmin(-30°,30°) ≤ N(60°,0°) ≤ Nmax(-30°,30°)? and should we also not rotate the light?
Welcome to PhysicsForums, xb4byish!

I don't follow your question either. However, if by chance you are referring to entangled photons: they cannot be considered as vertically polarized.

Mentor

## Polarized light; maximum number of disagreements?

What are Nmin(-30°,30°), N(60°,0°) and Nmax(-30°,30°)?

What do you mean with maximum number of disagreements? Maximal number of photon pairs where two detectors will see different orientations for both photons? That is just the number of photon pairs. The average number is more meaningful.
 perhaps its average number of disagreements. But i mean how can we prove the number of disagreements for (60,0) is between the minimum number of disagreements of (-30,0) and the maximum number of disagreements between the maximum number of disagreements of (30,0)
 Mentor I don't understand that question. There is an explicit formula for the "disagreement probability", you can derive it simply by looking at the 4 different cases. That should help.

 Tags #photons