Potentiometric titration by ''mathematica''by emissivity Tags: mathematica, potentiometric, titration 

#1
Nov1412, 04:40 AM

P: 4

1. The problem statement, all variables and given/known data
at first, please look at this link http://upload.wikimedia.org/wikipedi...ithlegend.JPG as you know, potentiometric titration's data makes this graph. and first derivative, 2nd derivative etc.. I haven't tried this experiment yet. So I'd like to try this by the data which I just make by myself. this is not my real data. data = {{0, 1.0}, {2.5, 1.2}, {5.0, 1.3}, {7.5, 1.5}, {10.0, 1.7}, {12.5, 2.0}, {15.0, 7.0}, {17.5, 11.9}, {20.0, 12.1}, {22.5, 12.3}, {25.0, 12.4}, {27.5, 12.5}, {30.0, 12.5}} 2. Relevant equations derivatives 3. The attempt at a solution 1. I plotted the data. ListPlot[data] 2. and I used interpolation. f=Interpolation[data] 3. I plotted the graph Plot[f[x], {x, 0, 30}] there is a problem. If you try this, you would find out, near the end point, it doesnt fit well. I want the graph just like the link as I mentioned first (http://upload.wikimedia.org/wikipedi...ithlegend.JPG) well.. I know that I can draw these graph by my hand by the excel. just write the data, plot the graph, and I find dy/dx one by one and draw the 1st derivative graph, and d2y/dx2 one by one.. ... but as you know, I think this stupid doing is not good So I just want to plot the data easily by the mathematica.. is there any way to draw the data easily? or just I have to plot the graph one by one? please help me.. 



#2
Nov1412, 04:51 AM

Admin
P: 22,712

Try to use more data points, and make them more dense around the important places.
Not trhat I know it will work, just guessing. 



#3
Nov1412, 05:13 AM

P: 4

dear borek
then could you help me plot the 1st derivative graph? 



#4
Nov1412, 07:46 AM

P: 4

Potentiometric titration by ''mathematica''
well I got it
but I don't know how to delete this post I'll figure it out wait a sec.. 



#5
Nov1412, 07:51 AM

P: 4

well....
is there anyone who can tell me how to delete this post? sorry.. 


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