Need proof re prime of the form 8N +/-1

by ramsey2879
Tags: primes, squares, triangular numbers
 P: 891 I need help or direction on how to prove that if A = S^2 - (T^2 + T)/2 Then 8A-1 can not be factored into the form B*C where B and C are coprime and each of the form 8N+/-3. For instance -4*8-1 = -33 can be factored as -3*(8+3) and 5*8-1 = 39 = 3*(8*2-3). Thus neither -4 or 5 can be expressed as S^2 -(T^2+T)/2 where S and T are integers. So far I have proven that if A = f(S,T) = S^2 - (T^2+T)/2 then A = f(S',T') where S' = 3S + 2T +1 and T' = 4S + 3T + 1, but I don't know where to go from there. Any ideas.
 P: 39 S^2 = 1, 4, 9, 16, 25 ... (T^2 +T)/2 = 1, 3, 6, 10, 15, 21... 9-1 = 8; 8*8-1 = 63; 63 = 3*(8*3-3). therefore your statement is false. edit: nm, missed the co prime part. okay; i programmed a check up to many values, as far as i can tell this is true. how to prove ti is beyond me though.
P: 891
 Quote by phillip1882 S^2 = 1, 4, 9, 16, 25 ... (T^2 +T)/2 = 1, 3, 6, 10, 15, 21... 9-1 = 8; 8*8-1 = 63; 63 = 3*(8*3-3). therefore your statement is false. edit: nm, missed the co prime part. okay; i programmed a check up to many values, as far as i can tell this is true. how to prove ti is beyond me though.
Thankyou for your post. Glad to see that someone was interested enough to check my apparent finding.

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P: 8,912

Need proof re prime of the form 8N +/-1

Suppose p is prime, 3 or 5 mod 8.
Easy to show that p cannot be expressed as 2*a2-b2.
Also seems to be true that if p|2*a2-b2 then so does p2. That looks like it might be associated with your observation.
 P: 144 Hi Ramsey, your observation is a consequence of the following: Lemma: Let N=2x2-y2 with x and y integers. Let p|N be a prime of the form 8ką3. Then ordp(N) is even. (By ordp(N) we mean the exponent of p in the factorization of N.) Proof: First recall that 2 is a quadratic residue modulo a prime q if and only if q is of the form 8ką1. Since p|N we have 2x2 = y2(mod p). Since 2 is a quadratic nonresidue, it follows that y=x=0 (mod p), and all the terms of the equation N=2x2-y2 can be divided by p2. Repeat as long as N has prime factors of the form 8ką3, and qed. Your observation follows immediately from this by setting N=8A-1, x=2S, y=2T+1, and by observing that in a coprime factorization N=bc, all factors pa are of the form 8ką1. I assume the lemma is well known, but I couldn't immediately find a reference. It is analogous to the celebrated theorem about sums of two squares, one version being: A positive integer N can be written as a sum of two squares if and only if for all primes p of the form 4k+3, ordp(N) is even.

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