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The substended angle of a circle 
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#1
Nov2212, 09:17 AM

P: 102

Hello! I came across the following formula for the change in the subtended angle (of a circle), when we move our obersvation point [tex]\vec{x}[/tex] by [tex]\delta \vec{x},[/tex]
[tex]\delta \Omega = \oint \hat{x} \cdot \frac{(\delta \vec{x} \times d\vec{l})}{\vec{x}^2}. [/tex] The integration path is the circumference of the circle. Do you know any litterature or easy derivation that can prove this fact? Thanks for your help, really appreciated! 


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