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Notions of simultaneity in strongly curved spacetime |
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| Nov24-12, 02:39 PM | #120 |
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Notions of simultaneity in strongly curved spacetime |
| Nov24-12, 03:02 PM | #121 |
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| Nov24-12, 03:27 PM | #122 |
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I am interested only in two worldlines and relative rates of proper time along them. Try to draw spacetime diagram. You just project one worldline on other using identical null geodesics. There is no need for concept of "now".
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| Nov24-12, 04:13 PM | #123 |
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| Nov24-12, 06:42 PM | #124 |
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You can use this information to get distances, as long as you define exactly your notion of simultaneity. This definition of simultaneity defines how you split the Lorentz interval, which is a space-time interval and independent of the observer, into a part that's purely space-like (this depends on the observer) and a part that's purely time-like (which also depends on the observer). This is the domain of SR, and its my impression that a lot of people get lost at this point. Once you've managed the notion of simultaneity, you can slice 4-d space-time into a bunch of 3-d hypersurfaces of simultaneity. The distance then becomes defined in the usual way one defines distance on a possibly curved manifold. You can use the 4-d techniques to find the Lorentz interval between any two nearby points on hypersurface, and because you've defined the time difference to be zero you know that this Lorentz interval gives you the proper distance between the nearby points. So you've got an "induced metric" that lets you find the distance between any two nearby points on the hypersurface. Given the infinite set of distances between all nearby points, you can find the curve of lowest distance connecting your two points, and call this the distance. The metric IS the space-time map, as described by Misner: http://arxiv.org/abs/gr-qc/9508043 |
| Nov24-12, 06:56 PM | #125 |
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Use of the static frame's defintion of "now" is fine as long as none of your observers are moving. When you start to have moving observers (such as the ones falling into a black hole), the moving observers will have a different defintion of "now" than the static frame has. Use of the static frame's defintion of "now" also becomes problematical when one wants to examine events at or inside the event horizon, because static observers (and their static frame) no longer exist there. So people who reloy on the static observer's notion of "now" tend to get confused by trying to apply it as if it existed in regions where it doesn't. As a result we get these long, meandering threads. So short summary: Use of the static observers "now" in the external region of a black hole is fine. Trying to apply it to the event horizon or inside a black hole just doesn't work. It also doesn't work if you want to consider moving observers, such as those external to the event horizon who are falling in, if they are moving at relativistic velocities. |
| Nov25-12, 02:41 AM | #126 |
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But of course static spacetime (spacetime with static curvature) is needed for this to work. |
| Nov25-12, 02:51 AM | #127 |
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You are correct that, strictly speaking, your definition of "which clock runs faster" does not "require" a concept of "now"; you are basically using null curves as references, whereas the other definition of "which clock runs faster" uses spacelike surfaces of constant time, i.e., "now" surfaces, as references. But the difference is really immaterial: both definitions only work in static spacetime regions, so they both cover exactly the same set of cases; and one can always translate freely between them, so there is no reason other than personal preference for choosing one over the other. |
| Nov25-12, 02:59 AM | #128 |
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But he explains what he means with additional statements and it requires a bit of thinking over. |
| Nov25-12, 09:17 AM | #129 |
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To me it seems that they have different "now" and that is the main difference between them. GP is based on time of moving observers but coordinate orgin is the same as for stationary observer and radial distance too is from SC coordinates. PeterDonis: you made the same (or very similar) statement. What do you think about "now" of SC vs "now" of GP coordinates? |
| Nov25-12, 01:38 PM | #130 |
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| Nov25-12, 04:12 PM | #131 |
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Offhand, I don't see any problem with your statement about the main difference between GP coordinates and SC coordinates being the assignment of the time coordinate. Perhaps problems with it will show up later, but at the moment I think it's OK. GP coordinates are sort of a hybrid coordinate system, they've got the time coordinates of the infalling observers mixed with the space coordinates of the static observers. But they're mathematically pretty convenient to use for many purposes. |
| Nov25-12, 08:41 PM | #132 |
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| Nov26-12, 12:13 AM | #133 |
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So where is the catch? We have two coordinate systems with different "now", object with static spatial coordinates in one coordinate system has static spatial coordinates in other coordinate system as well. |
| Nov26-12, 12:22 AM | #134 |
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In the non-static coordinate system (GP coordinates), the metric is not diagonal; there is a dt dr "cross term" in the line element. That means the surfaces of constant GP time are *not* orthogonal to the worldlines of objects with static spatial coordinates. And that means the definition of "now" given by GP coordinates is *different* than the definition of "now" given by the local inertial frames along the worldlines of objects with static spatial coordinates. So the sense in which the definition of "now" given by static (SC) coordinates is "unique" is that it is the only one that matches up with the definition of "now" in the local inertial frames of static observers. |
| Nov26-12, 01:25 PM | #135 |
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Now that my urgent questions concerning Oppenheimer-Snyder having been answered (thanks Peter), I'm returning to this thread. Atyy gave here an interesting link on which I already commented there. Retake:
I wonder if you mean that a symmetrical interpretation can be valid. That can't be correct: Eve is the one who fires the rocket engines and feels a force, in contrast to Adam. Compare https://en.wikisource.org/wiki/Relat..._of_Relativity "This is by no means true for all gravitational fields, but only for those of quite special form. It is, for instance, impossible to choose a body of reference such that, as judged from it, the gravitational field of the earth (in its entirety) vanishes." [..] Even though by no means all gravitational fields can be produced in this way [= from acceleration], yet we may entertain the hope that the general law of gravitation will be derivable from such gravitational fields of a special kind. " - starting from section 20 of: https://en.wikisource.org/wiki/Relat..._of_Relativity And a modern point of view (for there is by far no unity): "A gravitational field due to matter exhibits itself as curvature in spacetime. [..] modern usage demotes the uniform "gravitational" field back to its old status as a pseudo-field. " - http://math.ucr.edu/home/baez/physic...x/twin_gr.html ![]() In contrast, according to Einstein, clocks in a gravitational field go at different rates - much more different than what he should conclude according to you. |
| Nov26-12, 02:24 PM | #136 |
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