
#1
Nov2712, 11:10 AM

P: 72

I have been told to calculate the pressure drop between two points in a pipe carrying water using a Utube manometer. I understand that the pressure drop (P_{1}  P_{2}) is given by pgh and that h is the difference in manometer fluid levels and g is gravity, but is p the density of the manometer fluid or the water flowing through the pipe?




#2
Nov2812, 11:10 AM

P: 90

Exactly, p1p2 = gh(density(manometer fluid)  density(water))




#3
Nov2912, 09:36 PM

P: 72





#4
Nov2912, 11:03 PM

P: 90

U tube manometer
it is not a good idea to use a fluid of lower density in manometer than the density of fluid in the pipe. a higher density fluid is used to make measuring instruments smaller. for example, mercury will require a space 13.6 times smaller than water for same pressure rise or drop.



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