Register to reply 
U tube manometer 
Share this thread: 
#1
Nov2712, 11:10 AM

P: 72

I have been told to calculate the pressure drop between two points in a pipe carrying water using a Utube manometer. I understand that the pressure drop (P_{1}  P_{2}) is given by pgh and that h is the difference in manometer fluid levels and g is gravity, but is p the density of the manometer fluid or the water flowing through the pipe?



#2
Nov2812, 11:10 AM

P: 91

Exactly, p1p2 = gh(density(manometer fluid)  density(water))



#3
Nov2912, 09:36 PM

P: 72




#4
Nov2912, 11:03 PM

P: 91

U tube manometer
it is not a good idea to use a fluid of lower density in manometer than the density of fluid in the pipe. a higher density fluid is used to make measuring instruments smaller. for example, mercury will require a space 13.6 times smaller than water for same pressure rise or drop.



Register to reply 
Related Discussions  
Manometer U Tube  Introductory Physics Homework  1  
Utube manometer fluid mechanics  Classical Physics  0  
Hydrostatic Problem: Three tube Manometer  Introductory Physics Homework  2  
3 tube Manometer Q PLEASE HELP  Engineering, Comp Sci, & Technology Homework  0  
Fluid mechanics  u tube manometer  Introductory Physics Homework  0 