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Please help transistor amplifier

by michael1978
Tags: amplifier, transistor
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michael1978
#91
Nov25-12, 11:55 AM
P: 133
haha i rely dont find i find one like min 0.050+10*0.050=0.55, joney were i make now mistake, with my calculator pfff i am shame

JONEY can you tell me please how to calculate in my calculator please
michael1978
#92
Nov25-12, 12:05 PM
P: 133
Joney i know you know how to do it with calculator, can you tell me because i have in my hand calculator, i can find nothing in google the same result please....
Jony130
#93
Nov25-12, 12:06 PM
P: 406
Simply use your brain instead of a calculator.
And if you still don't know how you should quit EE and start learn math.
michael1978
#94
Nov25-12, 12:13 PM
P: 133
Quote Quote by Jony130 View Post
Simply use your brain instead of a calculator.
And if you still don't know how you should quit EE and start learn math.
JONEY i use me brain, why you dont tell me to calculate with my calculator, you just help me, i thank you for help, just tell me a little bit, and i use a calculator, you help so much, help also this one
Jony130
#95
Nov25-12, 12:15 PM
P: 406
But I don't understand what is your problem?
I_R1 = 50uA + 10*50uA = 50 + 500 = 550uA = 0.55mA = 0.00055A
michael1978
#96
Nov25-12, 12:28 PM
P: 133
Quote Quote by Jony130 View Post
But I don't understand what is your problem?
I_R1 = 50uA + 10*50uA = 50 + 500 = 550uA = 0.55mA = 0.00055A
joney i know this from begin to calculate this is easy, but my problem was other you forget,
i ask you for this

-------------------------------
o sorry joney i make you tired, i understand now, so if load current is 50μ we chose voltage divider current 10 larger then the load current, and we have

R2 = 1.7V/(10*Iload) = 1.7V/((this is 10 time larger)10*50μ(base current)) = 1.5V/500μA = 3.4K this i understand

but this i dont understand
I_R1 = 10*Iload + Iload = 11*Iload = 550μA

10*Iload(50μA)+Iload(50μA)=11(how we get 11 now)*Iload(50μA)=550μA

i dont understand that 11 how we get? 10*Iload(50μA)+Iload(50μA)=0.55 not 11 sorry i dont know where i make mistake, where come this 11, i dont know how to calculate, i know 11*Iload is 550μA
thnx for answer
----------------------------------
joney this 11 is my problem
Jony130
#97
Nov25-12, 12:34 PM
P: 406
OMG
Look here
We have this equation
B = 10*A + A = 11*A
The first part tell as that we have a ten apples and we need add one more apple.
So we end-up with eleven apples .
michael1978
#98
Nov25-12, 12:41 PM
P: 133
Quote Quote by Jony130 View Post
OMG
Look here
We have this equation
B = 10*A + A = 11*A
The first part tell as that we have a ten apples and we need add one more apple.
So we end-up with eleven apples .
ah you mean so
10*0.0.5+0.0.5=
10+0.5+0.5=11

you mean like this
michael1978
#99
Nov25-12, 12:56 PM
P: 133
ooh joney boy, i make again mistake of is right, ooo thank you try a lot to explain me
Jony130
#100
Nov25-12, 02:22 PM
P: 406
In our cases we have 11 apples
B = 10*A + A

And apples are equal to 50uA of load current.
So we substitute for A = 50uA
B = 10*50uA + 50uA = 550uA
And this is equal to 11*A = 11*50 = 550uA
the 11 tell as that the R1 current is 11 times large the load current.
michael1978
#101
Nov25-12, 02:27 PM
P: 133
Quote Quote by Jony130 View Post
In our cases we have 11 apples
B = 10*A + A

And apples are equal to 50uA of load current.
So we substitute for A = 50uA
B = 10*50uA + 50uA = 550uA
And this is equal to 11*A = 11*50 = 550uA
the 11 tell as that the R1 current is 11 times large the load current.
thank you joney for losing time for me and help i go to sleep tomorow work have a nice sleep
michael1978
#102
Nov25-12, 02:31 PM
P: 133
thank you ver much joney now i start to understand
michael1978
#103
Nov26-12, 11:20 AM
P: 133
Quote Quote by michael1978 View Post
thank you ver much joney now i start to understand
hi joney, may i ask you something

if we take 10 large then load(50micro)this is all time formula
for i_R2=10*LOAD and I_R1 = 10*Iload + Iload = 11*Iload = 550μA
and
if we take 5 large then load(50micro)this is all time formula
for i_R2=5*LOAD and I_R1 = 5*Iload + Iload = 11*Iload =
is correct?

and can you tell me wich book, do you know some book where i can learn good electronics?
advice
now i am reading electronics principles 7 by malvino
Jony130
#104
Nov26-12, 11:46 AM
P: 406
if we take 5 large then load(50micro)this is all time formula
for i_R2=5*LOAD and I_R1 = 5*Iload + Iload = 11*Iload =
is correct?
Check your algebra skills because your answer is wrong.

B = 5A + A = ??


and can you tell me wich book, do you know some book where i can learn good electronics?
advice
now i am reading electronics principles 7 by malvino
I don't know any good book. Try buy a book in your native language.
michael1978
#105
Nov27-12, 11:01 AM
P: 133
Quote Quote by Jony130 View Post
Check your algebra skills because your answer is wrong.

B = 5A + A = ??



I don't know any good book. Try buy a book in your native language.
is 6 i know now,

but the best books are in engish
michael1978
#106
Nov27-12, 11:25 AM
P: 133
CAN I KNOW, wich electronic software you use
michael1978
#107
Nov28-12, 08:50 AM
P: 133
joney my dear, are you here somewhere, i just wana say thank you for help, losing time for me....
Jony130
#108
Nov28-12, 11:19 AM
P: 406
Quote Quote by michael1978 View Post
but the best books are in engish
I don't think so.
Quote Quote by michael1978 View Post
CAN I KNOW, wich electronic software you use
I use LTspice, but circuit simulations are not good for beginners.
Circuit simulators are worthless, or worse, if you don't understand your circuit pretty well before you simulate it. Still, it won't hurt you to play with it, so long as you always keep in mind that garbage in = garbage out, or, in the case of simulators, garbage in=sophisticated garbage out.


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