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Please help transistor amplifier 
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#91
Nov2512, 11:55 AM

P: 133

JONEY can you tell me please how to calculate in my calculator please 


#92
Nov2512, 12:05 PM

P: 133

Joney i know you know how to do it with calculator, can you tell me because i have in my hand calculator, i can find nothing in google the same result please....



#93
Nov2512, 12:06 PM

P: 406

Simply use your brain instead of a calculator.
And if you still don't know how you should quit EE and start learn math. 


#94
Nov2512, 12:13 PM

P: 133




#95
Nov2512, 12:15 PM

P: 406

But I don't understand what is your problem?
I_R1 = 50uA + 10*50uA = 50 + 500 = 550uA = 0.55mA = 0.00055A 


#96
Nov2512, 12:28 PM

P: 133

i ask you for this  o sorry joney i make you tired, i understand now, so if load current is 50μ we chose voltage divider current 10 larger then the load current, and we have R2 = 1.7V/(10*Iload) = 1.7V/((this is 10 time larger)10*50μ(base current)) = 1.5V/500μA = 3.4K this i understand but this i dont understand I_R1 = 10*Iload + Iload = 11*Iload = 550μA 10*Iload(50μA)+Iload(50μA)=11(how we get 11 now)*Iload(50μA)=550μA i dont understand that 11 how we get? 10*Iload(50μA)+Iload(50μA)=0.55 not 11 sorry i dont know where i make mistake, where come this 11, i dont know how to calculate, i know 11*Iload is 550μA thnx for answer  joney this 11 is my problem 


#97
Nov2512, 12:34 PM

P: 406

OMG
Look here We have this equation B = 10*A + A = 11*A The first part tell as that we have a ten apples and we need add one more apple. So we endup with eleven apples . 


#98
Nov2512, 12:41 PM

P: 133

10*0.0.5+0.0.5= 10+0.5+0.5=11 you mean like this 


#99
Nov2512, 12:56 PM

P: 133

ooh joney boy, i make again mistake of is right, ooo thank you try a lot to explain me



#100
Nov2512, 02:22 PM

P: 406

In our cases we have 11 apples
B = 10*A + A And apples are equal to 50uA of load current. So we substitute for A = 50uA B = 10*50uA + 50uA = 550uA And this is equal to 11*A = 11*50 = 550uA the 11 tell as that the R1 current is 11 times large the load current. 


#101
Nov2512, 02:27 PM

P: 133




#102
Nov2512, 02:31 PM

P: 133

thank you ver much joney now i start to understand



#103
Nov2612, 11:20 AM

P: 133

if we take 10 large then load(50micro)this is all time formula for i_R2=10*LOAD and I_R1 = 10*Iload + Iload = 11*Iload = 550μA and if we take 5 large then load(50micro)this is all time formula for i_R2=5*LOAD and I_R1 = 5*Iload + Iload = 11*Iload = is correct? and can you tell me wich book, do you know some book where i can learn good electronics? advice now i am reading electronics principles 7 by malvino 


#104
Nov2612, 11:46 AM

P: 406

B = 5A + A = ?? 


#105
Nov2712, 11:01 AM

P: 133

but the best books are in engish 


#106
Nov2712, 11:25 AM

P: 133

CAN I KNOW, wich electronic software you use



#107
Nov2812, 08:50 AM

P: 133

joney my dear, are you here somewhere, i just wana say thank you for help, losing time for me....



#108
Nov2812, 11:19 AM

P: 406

Circuit simulators are worthless, or worse, if you don't understand your circuit pretty well before you simulate it. Still, it won't hurt you to play with it, so long as you always keep in mind that garbage in = garbage out, or, in the case of simulators, garbage in=sophisticated garbage out. 


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