
#1
Dec312, 09:42 PM

P: 4

Im trying to calculate the orbit of a planet rotating a star after "x" amount of mass has been transfered form the planet to the star. I took our own solar system for example and assumed earth was the only planet orbiting the sun.
I used the orbit equilibrium equation : (GM1M2)/ R = M2 (V)2 where m1 is the mass of the sun and m2 is mass of the earth, v is earth's orbital velocity and r is its orbital radius. then i added the value x to m1 and subtracted it from m2 ( mass added to the sun and stolen from earth), getting : (G(M1+x)(M2x))/ R = (M2x) (V)2 but V or orbital velocity is simply: V= [G(M1+x)/R]^1/2 Substituting that back into our equilibrium equation, we get: (G(M1+x)(M2x))/ R = (M2x) ([G(M1+x)/R]^1/2)2 which is simplified to : G(M1+x)(M2x)/ R = (M2x)G(M1+x)/R As one can see , the terms "R" and "G" can be canceled out from both sides , giving: (M1+x)(M2x)= (M2x)(M1+x) Which implies that no matter how much mass is transfered from an orbiting body to the body being orbited , the orbital radius WILL NOT change. ONLY the orbital speed would change. Is this the right conclusion or did I go wrong somewhere ??? 



#2
Dec512, 01:20 AM

P: 4

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