
#1
Dec512, 10:29 AM

P: 1

Hi, having a bit of trouble with this question
"In an argon ion laser ( λ = 514nm) the minimum beam waist is 1.0mm and is close to the plane mirror. Calculate the radius of curvature of the beam at the output mirror. 1.15m away" Attempt at a solution: θ = 2λ/pi W0^{2} R = Z + Z_{R}^{2}/Z Z_{R} = piW_{0}^{2} / λ I used W0 = min beam waist = 1.00 mm Z= distance from beam waist to mirror = 1.15m And found Z_{r} with the formula and used it in the Radius of curvature, R formula but got the worng answer. I got R = 33.5m The answer given is R = 3.08m 



#2
Dec612, 12:03 PM

P: 149

Beam width isn't beam radius!



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