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Kronecker Delta and vector form of q_(i,j) q_(m,mj) 
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#1
Dec512, 03:18 PM

P: 14

guys,
we know ∇q=q_{i,j} and ∇ ∇.q=q_{i,ij} but what will happen if we have q_{i,j}q_{m,mj} ? (sum on j) I know some terms of ∇q∇ ∇.q will drop due to that summation. so the question is what is the right expression in vector form for that term. thanks 


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