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angled light path in moving clock |
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| Dec15-12, 01:57 PM | #1 |
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angled light path in moving clock
1. Ann's light clock uses a single photon that oscillates vertically between two mirrors separated by a distance d. She leaves the space station, accelerates to a constant .2c in a random direction labeled x.
For her clock to continue working, the photon must move vertically as before, and simultaneoulsly horizontally along x. If the photon does not aquire the speed of the clock, it must move at an angle relative to the vertical. What causes the angular orientation? 2. Assume the same scenario except the upper mirror is moved vertically to a separation of d/2. Does the clock still work? |
| Dec15-12, 02:09 PM | #2 |
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If Ann remains still, an observer moving past at any velocity such as 0.2c will see her clock continue to work properly. The photon's velocity will appear to have a sideways component just as the mirrors in the clock do also.
However if you are serious that Ann accelerates, she must push her clock along with her. She will push the mirrors and they will accelerate, but there is nothing to push the photon and it will fall off the edge. |
| Dec18-12, 10:56 AM | #3 |
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If the clock only works for a specific speed, i.e. in the frame where it was constructed, this would seem to disagree with the 1st postulate. This also relates to the laser pointed toward the ceiling of a moving capsule. Does it work for an observer moving at various speeds? |
| Dec18-12, 11:05 AM | #4 |
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angled light path in moving clock |
| Dec18-12, 11:23 AM | #5 |
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I'm only considering constant speeds. This is based on the speed of light being constant and independent of the source. If either device, light clock or laser, moves to the right, the original vertical beam must move to the right to function correctly. The goal is to explain how the light signal aquires the necessary angle to intercept the moving mirror or ceiling that is vertical relative to the observer moving with the device. I've never seen an explanation for this. |
| Dec18-12, 11:52 AM | #6 |
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| Dec18-12, 12:25 PM | #7 |
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| Dec18-12, 12:26 PM | #8 |
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| Dec18-12, 12:52 PM | #9 |
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| Dec18-12, 01:03 PM | #10 |
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This is equivalent to the transverse light path of the Michelson-Morley experiment, where one also expects an inclined path to the right due to momentum conservation (in the aether frame). See the lower image at Wikipedia/Michelson-Morley. There you can see how photons gain momentum and thus direction from the source, without changing the photon's speed. If you transform back into the MMX frame, the path becomes a straight line in transverse direction again. |
| Dec19-12, 11:44 PM | #11 |
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| Dec20-12, 12:32 PM | #12 |
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Thanks for all responses.
Histspec's is consistent with the mass-energy equivalence which affects the light path near a massive object as verified in the 1919 experiment. This is also my basic understanding from reading Max Born's explanation in his book on Relativity. Having read Feymann's book on light propagation, I also leave room for revisions! |
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