# Calculating temperature increase in a building as a result of solar radiation

 P: 7 I'm working on a thermal balance of a building. In particular, I'm trying to calculate the effect energy gains (mostly due to solar radiation) have on the inside temperature of the building. So I calculated the energy gains per month, for instance, 20 kW for the month of February (it's an extremely poorly insulated building). The only way I know of relating heat, temperature, and mass, is through the equation: Q=m.cp.dT where: - Q is the heat in kJ - m is the mass of air in kg - cp is the specific heat of air in kJ/kg.K - dT is the temperature difference in K (Note: I'm using the dot to represent thousands and the comma to represent decimals) So, in one hour, we have 20 kWh, which is 72.000 kJ. For a volume of 637 m3 (the volume of the building) and a density of air of 1,2 kg/m3, we end up having 764 kg of air. If we consider the specific heat of air to be 1,0 kJ/kg.K, then dT is 94 K. I must admit the number shocked me, so much so that I think I'm doing something wrong. Is there something I'm missing here? Theoretically, if I had a perfectly insulated volume of 637 m3 of air, and I heated it during 1 hour with 20 kW, then it's correct that said volume would experiment a temperature increase of 94°C? Finally, in the case of a poorly insulated building (it has three sliding-glass walls and a corrugated steel pitched roof), how much could I expect the inside temperature to rise in summer? In other words, how can I accurately calculate temperature increase in a building as a result of solar radiation gains? Thanks.
 Mentor P: 12,023 You can neglect the air, unless you care about short-term effects from ventilation. The heat capacity of solid materials will dominate the total heat capacity. There is an easy way to see this: The mass of the building itself is much more than 760kg.
 Sci Advisor Thanks PF Gold P: 12,238 If you had 20kW worth of central heating and you ran it for an hour, an average house would be 'very cosy' and that would be a real building with many heat loss mechanisms (which are going to lose heat proportional to the temperature difference). After an hour the walls and contents would have started to warm up and the heat capacity of those and all the other contents. Years ago, I decided to get central heating installed in my home and I estimated the size of radiators needed for each room for a given temperature rise etc, etc. The answer I got was laughably small - until I realised that you need to take air exchange into account. I then got some sensible answers. The guy who did the installation then went and ordered different ones and the house was always very comfortable!! So much for theory. (I think he bought the cheapest sizes so I'm not complaining.)
P: 7
Calculating temperature increase in a building as a result of solar radiation

 Quote by mfb You can neglect the air, unless you care about short-term effects from ventilation. The heat capacity of solid materials will dominate the total heat capacity. There is an easy way to see this: The mass of the building itself is much more than 760kg.
What exactly do you mean by, "you can neglect the air"? Heat gains will invariably rise the temperature inside the building, won't they?
P: 7
 Quote by sophiecentaur If you had 20kW worth of central heating and you ran it for an hour, an average house would be 'very cosy' and that would be a real building with many heat loss mechanisms (which are going to lose heat proportional to the temperature difference). After an hour the walls and contents would have started to warm up and the heat capacity of those and all the other contents.
Okay, so 20kW is not that random a number then. Thanks.
Thanks
PF Gold
P: 12,238
 Quote by OdanUrr Okay, so 20kW is not that random a number then. Thanks.
Bearing in mind that rich, nerdy people actually do build themselves houses that need no extra heating, there must be enough solar energy available to your house to keep it warm. That 20kW is certainly in the right ball park.

Going to the situation of high summer in a hot climate, you can expect to have a similar amount of heat to get rid of in order to stay comfortable.
P: 7
 Quote by sophiecentaur Bearing in mind that rich, nerdy people actually do build themselves houses that need no extra heating, there must be enough solar energy available to your house to keep it warm. That 20kW is certainly in the right ball park. Going to the situation of high summer in a hot climate, you can expect to have a similar amount of heat to get rid of in order to stay comfortable.
Yes, that's why I'm going to use insulation in the model, to try and see if I can get rid of solar heat gains. I'm trying to create an insulated environment for an indoor pool.
Mentor
P: 12,023
 Quote by OdanUrr What exactly do you mean by, "you can neglect the air"? Heat gains will invariably rise the temperature inside the building, won't they?
Of course. Where is the connection between both?
Heat capacity of buildings is dominated by the heat capacity of the building itself and not its air. The heat capacity of air can be relevant for heating/ventilation.
You can quickly cool (or heat) the air by several degrees if you open a window. But as soon as you close the window again, temperature will quickly return to its previous value (with some very small drop) as the walls heat the air again.
Thanks
PF Gold
P: 12,238
 Quote by mfb Of course. Where is the connection between both? Heat capacity of buildings is dominated by the heat capacity of the building itself and not its air. The heat capacity of air can be relevant for heating/ventilation.
This is true but only if all the windows are closed! If they are open, you need to consider all the air in the surrounding (and changing) atmosphere. In practical terms this has more effect on your heating bills than anything else.
P: 3,216
 So I calculated the energy gains per month, for instance, 20 kW for the month of February
Perhaps I'm being picky but..

An "energy gain" is measured in Joules or possibly kWH if you insist. It's not measured in kW, that would be a power gain.

 how can I accurately calculate temperature increase in a building as a result of solar radiation gains?
I believe well insulated houses need to incorporate shading to avoid overheating from solar gain. I think there are computer programs available to simulate this but I've not investigated.

If you are getting into this for real I recommend joining The Green Building Forum and posting requests for info on passive houses over there. I think there might be a small one off joining fee but can't remember how much it is.

http://www.greenbuildingforum.co.uk

 Related Discussions General Physics 7 Earth 0 Engineering Systems & Design 2 Introductory Physics Homework 1 General Physics 4