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When moving at the speed of light time stops 
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#19
Dec3012, 06:28 AM

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That seems like a good way to put it. In your reference frame you are not moving at the speed of light, you experience time, and in your frame light takes time to go from A to B. And light doesn't have a reference frame of its own.



#20
Dec3012, 06:56 AM

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Thank you all, you have been a great help.
Last post puts it straight and simple. 


#21
Dec3012, 09:59 AM

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the lorentz transformation is singular for the speed of light i.e. Not defined



#22
Jan313, 02:41 PM

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What about this answer:
The time dilation formula is according to http://en.wikipedia.org/wiki/Time_dilation T‘ = T * sqrt (1v^{2}/c^{2}). Set v=c, the proper time of light T’ will always be 0. The lorentz transformation is not defined for the speed of light, but the time dilation formula above is. However, time is not frozen, the proper life time of a photon is zero. 


#23
Jan313, 06:05 PM

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#24
Jan313, 07:32 PM

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I don't think any of the previous posts have really addressed the basic misunderstanding invoved in the OP's question. The OP asked:
(1) (2) "If when you're moving close to the speed of light time freezes, why then does it take neutrinos 8 minutes to reach the earth from the sun?" The answer is that when we talk about the time taken for something to reach the earth from the sun, we're implicitly talking about the time as measured in the frame of the earth. But relativistic time dilation would relate the 8 minutes to the much longer time taken in the frame of the neutrino. A question that didn't involve this misconception would be: (3) If when you're moving close to the speed of light time freezes, does that mean that only a very short time passes in the frame of a neutrino that, in the earth's frane, takes 8 minutes to reach the earth? The answer would be yes. 


#25
Jan313, 11:04 PM

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Thanks, great answer!



#26
Jan413, 01:40 AM

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which one? are you (mistakenly?) refering to our current thread? Moonraker 


#27
Jan413, 01:48 AM

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#28
Jan413, 03:11 AM

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If you had read this thread you would have read this post: 


#29
Jan413, 04:38 AM

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#30
Jan413, 05:09 AM

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#31
Jan413, 05:45 AM

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#32
Jan413, 05:47 AM

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At the absorption, the clock of the observer shows 8 minutes (SunEarth). The “clock” of the photon shows 0 seconds, according to the abovementioned time dilation formula: T‘ = T * sqrt (1v^{2}/c^{2}), even if the Lorentz transformation does not apply to photons. 


#33
Jan413, 05:55 AM

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#34
Jan413, 06:06 AM

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#35
Jan413, 06:45 AM

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#36
Jan413, 07:26 AM

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