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Solutions to Ax^2 +By^2=(A+B)^(2n+1) 
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#1
Jan713, 12:40 AM

P: 894

No not the trival solution but generally GCD(x,y) = 1 when GCD(A,B)=1
[tex] x = \sum_{k=0}^{n}(A)^k*B^{nk}*\binom{2n+1}{2k+1}[/tex] [tex] y = \sum_{k=0}^{n}(B)^k*A^{nk}*\binom{2n+1}{2k+1}[/tex] My question is was this known before? Example A=8, B = 3, n = 1 x = 1*3*3  8*1*1 = 1; y = 1*8*3 3*1*1 = 21; 8*1^2 + 3*21^2 = 11^3 for n = 2, x = 131; y = 89; 8*131^2 + 3*89^2 = 11^5 


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