# Solving a system of 3 nonlinear equations

by EM_Guy
Tags: equations, nonlinear, solving
 P: 3 a = xyz b = xy+xz+yz c = x + y + z How do you solve x, y, and z?
 Mentor P: 9,703 x=c-y-z b=(c-y-z)y + (c-y-z)z + yz = c(y+z)-y^2-zy-z^2 Solve this quadratic equation for y (or z), use both in a=xyz and hope that it has a nice solution?
 P: 3 It is not a quadratic equation. And it is not a "nice" solution. I have determined that z^3-cz^2+bz-a = 0. So, if we can find the roots of the cubic function, then we have z as a function of a, b, and c. Then, it should be straightforward to find x and y in terms of a, b, and c. But I forget how to find the roots of a cubic function.
Mentor
P: 9,703

## Solving a system of 3 nonlinear equations

b= c(y+z)-y^2-zy-z^2 is a quadratic equation in y (or z).

Solutions of a cubic equation
z^3-cz^2+bz-a = 0 looks very nice in my opinion.

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