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Second order pde  on invariant? 
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#1
Jan2513, 12:52 PM

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What the meaning for a second order pde is rotation invariant?
Is all second order pde are rotation invariant? or only laplacian? 


#2
Jan2513, 10:13 PM

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P: 12,870

Well, do you know what "rotation invarient" means to start with?
It sounds like you've come across the terms as part of a course involving laplacians  in which case, you were shown a proof somewhere that the laplacian is rotation invarient. What was the condition the laplacian had to satisfy for the proof to work? Do all 2ndO PDEs satisfy this condition? 


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