second order pde -- on invariant?

by sigh1342
Tags: invariant, order
sigh1342 is offline
Jan25-13, 12:52 PM
P: 31
What the meaning for a second order pde is rotation invariant?
Is all second order pde are rotation invariant? or only laplacian?
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Simon Bridge
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Jan25-13, 10:13 PM
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Well, do you know what "rotation invarient" means to start with?
It sounds like you've come across the terms as part of a course involving laplacians - in which case, you were shown a proof somewhere that the laplacian is rotation invarient. What was the condition the laplacian had to satisfy for the proof to work? Do all 2ndO PDEs satisfy this condition?

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