
#1
Feb513, 10:09 PM

P: 21

This is very tricky for me. How to find the inverse laplace of 1s. I haven't been taught the integral method of inverse. Only the formula based , splitting terms kind of thing. I used matlab and found it was dirac delta. But how do I get to it without using the integral for inverse?




#2
Feb613, 12:52 AM

P: 38

When I look at this in Mathematica I get a derivative of the delta function, in other words:
[tex] \mathcal{L}^{1}\left\{s\right\} = \frac{d}{dt}\delta(t) [/tex] 



#3
Feb613, 01:33 AM

P: 21

inverse( df/dt)= s F(s) where laplace(f) = F(s) laplace ( dirac delta )=1 ( known property ) laplace( d(diracdelta)/dt ) = s*(1) hence, inverse( s) = d(diracdelta)/dt 



#4
Feb613, 01:19 PM

P: 90

Inverse laplace of 1s
Indianaronald,
Almost, be careful that: [itex]\mathcal{L}\left\{ \frac{\mathrm{d}f}{\mathrm{dt}} \left(t\right)\right\}=s\mathcal{L}\left\{f\left(t\right)\right\}[/itex] Not the inverse as you mentioned it. 



#5
Feb613, 10:07 PM

P: 21




Register to reply 
Related Discussions  
Laplace and inverse laplace transformation of unit step functions u(t).  Calculus & Beyond Homework  2  
IVP Laplace Transform Problem  Tricky Inverse Laplace Transform  Calculus & Beyond Homework  5  
Inverse Laplace Transformation of Inverse Tan function  Calculus & Beyond Homework  1  
Laplace & Inverse Laplace Transforms  Calculus & Beyond Homework  3  
Finding an inverse Laplace Transform for a function  solving IVPs with Laplace  Calculus & Beyond Homework  2 