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Excited states and selection rules

by Gregg
Tags: rules, selection, states
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Gregg
#1
Feb18-13, 11:22 AM
P: 463
If you have a meson in the states

## ^3S_1## and ## ^1S_0 ## this means that ##J^P = 1^+ ## and ## 0^+## doesn't it?

But if you have excited states

## ^1P_1 ## this is ##J^P=1^- ## but isn't ## ^3P_1 ## supposed to be ##J^P = 1^- ##? Does this matter?

##^3P_0##, ##^3P_1## and ##^3P_2## for the triplet with ## |L-S| \le J \le L+S ## what are the values ##J=0,1,2## referring to physically. ##L## is the orbital angular moment of the two quarks, and S is their spin, so for them to couple in a way that gives ##J=2## what does that mean?
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