Register to reply 
Integral of function over ellipse 
Share this thread: 
#1
Feb2713, 01:27 PM

P: 52

Hi,
I'm trying to find [tex] \iint_S \sqrt{1\left(\frac{x}{a}\right)^2 \left(\frac{y}{b}\right)^2} dS [/tex] where S is the surface of an ellipse with boundary given by [itex]\left(\frac{x}{a}\right)^2+\left(\frac{y}{b}\right)^2 = 1 [/itex]. Any suggestions are appreciated! Thanks, Nick 


#2
Feb2713, 02:35 PM

P: 643

Do you mean the interior of an ellipse?
Anyway, the first thing I though of is Green's Theorem for some reason. Probably since then we can make the substitution ##\left(\dfrac xa\right)^2+\left(\dfrac yb\right)^2=1##. The second thing I thought of was a change of coordinates and a multiplication by the Jacobian determinant, then we have it reduced to $$a\cdot b\cdot\iint_C\sqrt{1m^2n^2}\mathrm{d}S'$$ where C is the unit circle wrt m and n and S' should have a fairly obvious definition. 


#3
Feb2713, 02:38 PM

HW Helper
Thanks
PF Gold
P: 7,721

Try the substitution$$
\frac x a = r\cos\theta,\,\frac y b = r\sin\theta$$ 


#4
Feb2713, 06:10 PM

P: 52

Integral of function over ellipse
Got it!
Thanks 


Register to reply 
Related Discussions  
Set up polar area integral of ellipse  Calculus & Beyond Homework  3  
Green's theorem integral over an ellipse  Calculus & Beyond Homework  1  
Integral over a Rotated Ellipse  Calculus & Beyond Homework  2  
Line integral around an ellipse  Calculus & Beyond Homework  8  
Area of ellipse integral.  Calculus & Beyond Homework  13 