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A Simple Problem that seems to elude me... 
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#1
Feb205, 12:53 PM

P: 12

My mind is blank for some reason as I can't seem to figure out how to set up this problem...
It takes Steve and Dale together 10 hours to paint a house. Steve takes 30 hours by himself. How long would it take Dale to paint the house my himself? Thanks... 


#2
Feb205, 12:57 PM

P: 506




#3
Feb205, 01:17 PM

P: 12

OK,
Steve paints 1 house in 30 hours or 1/3 house in 30/3 = 10 hours That means that Dale has to paint the other 2/3 of the house in the 10 hour period. Working backwards for Steve, to get from the 10 hours together to his single total, we multiply 10 by 3/1 = 30 hours. So, for Dale, we have to multiply 10 * 3/2 to get 30/2 or 15 hours to paint the house by himself. I think... 


#4
Feb205, 01:42 PM

Sci Advisor
HW Helper
P: 11,928

A Simple Problem that seems to elude me...
Yes,15hrs is the correct answer...
Daniel. 


#5
Feb205, 02:13 PM

P: 12

Thanks....



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