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Partial DIfferential Equations problems

by stunner5000pt
Tags: differential, equations, partial
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Oct5-05, 12:06 PM
P: 1,440
Here is one of them - i posted it in another thread and i am getting help in there

this is another of my problems
Show that if C is a piecewise continuously differentiable closed curve bounding D then the problem
[tex] \nabla^2 u= -F(x,y) \ in\ D[/tex]
[tex] u = f \ on \ C_{1} [/tex]
[tex] \frac{\partial u}{\partial n} + \alpha u = 0 \ on \ C_{2} [/tex]
where C1 is a part of C and C2 the remainder and where alpha is a positive constant, has at most one solution.

now i know that [tex] \nabla^2 u = \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = -F(x,y) [/tex]

now im not quite sure how to connect the C1 part to C2 part...
would it be something liek C= C1 + C2?

but how would one go about showing that this has at most ONE solution?? I m not quite sure how to start ... Please help

another one
Show that the problem
[tex] \frac{\partial}{\partial x} (e^x \frac{\partial u}{\partial x} + \frac{\partial}{\partial y} (e^y \frac{\partial u}{\partial y} = 0 \ for \ x^2+y^2 < 1 [/tex]
u = x^2 for x^2 + y^2 = 1
has at most one solution
Hint Use the divergence theorem to derive an energy identity

Perhaps i dont remember a theorem i should have learnt in ap revious class... or i am not familiar with it but what would i use the divergence theorem here?
i eman i can get it down to this
[tex] e^x \frac{\partial}{\partial x} (u + \frac{\partial u}{\partial x}) + e^y \frac{\partial}{\partial y} (u + \frac{\partial u}{\partial y}) = 0 [/tex]
but hereafter i am stuck, please do advise!

Thank you!
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Oct5-05, 06:48 PM
P: 1,440
ok so i can rewrite the second euqation as

[tex] e^x \frac{\partial}{\partial x} (u + u_{x}) + e^y \frac{\partial}{\partial y} (u + u_{y}) = 0 [/tex]

also is [tex] u+ u_{x} [/tex] written as something else...
how would i apply the divergence principle here?
Oct6-05, 06:45 PM
P: 1,440
can anyone help me with this!

Physics Monkey
Oct6-05, 07:56 PM
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Partial DIfferential Equations problems

For the first problem, you might begin by assuming that two solutions exist which satisfy the differential equation and boundary conditions. The difference of the two solutions satisfies a simpler set of equations, right? Maybe this is a good place to start.

For the second problem, the original equation already looks like the divergence of a vector field in 2d. Maybe you should start from this observation.

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