How Do You Calculate Projectile Motion with Air Drag?

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Homework Help Overview

The discussion revolves around calculating projectile motion while incorporating air drag into the equations. The original poster is exploring the dynamics of projectile motion, particularly focusing on the effects of drag force represented by a quadratic relationship with velocity.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to derive an expression for vertical velocity over time, encountering difficulties with integrating and expressing velocity without using integrals or derivatives. Some participants suggest separating variables in the differential equation to find a solution. Others express confusion regarding the appearance of a tangent function in their calculations and question the validity of their resulting graphs.

Discussion Status

Participants are actively engaging with the mathematical aspects of the problem, with some providing guidance on the necessary steps to solve the differential equation. There is recognition of the need for initial conditions to properly define the solution, but no consensus has been reached on the correctness of the derived functions or their graphical representations.

Contextual Notes

There is mention of the original poster's uncertainty regarding their calculus skills and the complexity introduced by air drag in the projectile motion equations. The discussion also touches on the challenges of graphing the resulting functions and the use of LaTeX for formula representation.

villiami
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I have been working with projectile motion, and I am just starting to add air friction (drag) into the equations. I've run into a bit of a wall in terms of the calculations, so any help would be appriciated.

For a projectile, F(drag)=-c.V^2, where c is a constant (which can be written in terms of cross-sectional area, etc.)

Therefore: Acc(drag)=-c.V^2/(mass)


When I write an expression for vertical velocity [V(t)] at a given time [t], I get:

V(t) = V(initial) - 9.8t - (c/m). INTEGRAL{ [V(t)]^2 }dt


I then look at this equation and have trouble writting V(t) without an integral (or derivative for that matter).
I showed the problem to a friend, who gave me a strange tangent function for V(t), which I can't quite get my head around, as there is no mention of angles at this stage.


Maybe I'm on the wrong track, or maybe my calculus skills aren't quite up to scratch. Eventually I want to create a model for the projectile's motion (in terms of x and y), but first I need to get this part right.
Thanks for any help.
 
Last edited:
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Do you know how to separate variables in a differential equation?

Daniel.
 
Yes I realized that this is what I need to do to solve it (this resulted in an arctan funtion, which when rearranged gave me a tangent function for velocity). However, I was unsure how the tangent came out, and when I graphed the resulting function it did not look right. That's why I'm looking for some pointers.
Thanks,
villiami
 
This is your ODE

[tex]\frac{dv}{dt}=g -c \cdot v^{2}[/tex]

and you need to find [itex]v(t)[/itex] maybe with a initial condition giving the speed at t=0.

Daniel.
 
This then gives me [V is used instead of V(t)]:
dV/(g-cV^2)=dt
dV/[c(g/c-V^2)]=dt
INTEGRAL{1/c(g/c-V^2)}dV=INTEGRAL.dt
(1/sqrt[-g/c]).arctan(-Vc/g) = -cx + k; k is another constant
which eventually turns into:
V = (-g/c).tan{t.sqrt[-gc] + k.sqrt[-g/c]}
this doesn't seem to make sense when I draw the graph (I expected a curve with an asymptote at some terminal velocity)
Thanks,
Villiami
PS: how can I insert a formula? it takes me ages to write them in manually
 
Last edited:
We use Latex, basically write the code and let the compiler do the rest.

Daniel.
 

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