Bernoulli formula for integrals

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SUMMARY

The Bernoulli formula for calculating integrals is expressed as \(\int{f(x)dx}=C+\sum_{n=1}^{\infty}(-1)^{n}x^{n}\frac{d^{n}f}{dx^{n}}\frac{1}{\Gamma(n)}\). This series represents the antiderivative of the function \(f(x)\). The discussion raises the question of whether the integral can be computed from this series, highlighting the intriguing connection to Euler's gamma function rather than Bernoulli's numbers.

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eljose
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let be the Bernoulli formula for calculating an integral in the form:

[tex]\int{f(x)dx}=C+\sum_{n=1}^{\infty}(-1)^{n}x^{n}\frac{d^{n}f}{dx^{n}}\frac{1}{\Gamma(n)}[/tex]

my question is..could we calculate the integral from this series?..thanks.
 
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It's actually a series for the antiderivative. I don't see why not...

Daniel.

P.S. It's kinda mysterious that this formula involves Euler's gamma function and not Bernoulli's numbers.
 

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