- #1
jrodss
- 5
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1. The motion of a particle is described by x=10sin(pi*t+pi/3). At what time in s is the potential energy equal to the kinetic energy?
2. I know these equations come into play
Kinetic Energy
K=1/2*m*ω^2*A^2*sin^2(ωt+φ)
Kmax=1/2 k A^2
K=1/2 mv^2
Potential Energy
U=1/2*k*A^2*cos^2(ωt+φ)
U=1/2 kx^2
3. The Attempt at a Solution
Well I know A=10, w=pi, T=pi seconds I am really stuck on where to go from here I think I am trying to make it too complicated. Any pointers would be great. Also if someone could explain what the phase constant does to the equation it would be very helpful.
2. I know these equations come into play
Kinetic Energy
K=1/2*m*ω^2*A^2*sin^2(ωt+φ)
Kmax=1/2 k A^2
K=1/2 mv^2
Potential Energy
U=1/2*k*A^2*cos^2(ωt+φ)
U=1/2 kx^2
3. The Attempt at a Solution
Well I know A=10, w=pi, T=pi seconds I am really stuck on where to go from here I think I am trying to make it too complicated. Any pointers would be great. Also if someone could explain what the phase constant does to the equation it would be very helpful.