A Helium Balloon and Buoyancy

In summary: It should be the density of the water, as the buoyant force is caused by the displaced water.In this case, the buoyant force would be calculated using the density of air (1.28 kg/m^3) and the total volume of the system, which includes the volume of the balloon, basket, and helium. So the correct equation should be F_b = (1.28 kg/m^3) * (V_b + V_p + V_h) * g.
  • #1
TMO
45
1

Homework Statement



A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg1m-3 and the density of helium in the balloon is 0.18 kg1m-3. The radius of the balloon (when filled) is R = 5 m. The total mass of the empty balloon and basket is mb = 123 kg and the total volume is Vb = 0.066 m3. Assume the average person that gets into the balloon has a mass mp = 73 kg and volume Vp = 0.076 m3. What is the magnitude of the buoyant force on the entire system (but with no people)? Include the volume of the balloon, basket, and helium.

Homework Equations



[tex]V_{sph} = \frac{4}{3} \cdot \pi \cdot r^3[/tex]
[tex] F_b = \rho_{fluid} \cdot V \cdot g [/tex]

The Attempt at a Solution



Since the volume of the balloon and basket is given by [tex]V_b[/tex] and the volume of the balloon is given by [tex]\frac{4}{3} \cdot \pi \cdot R^3,[/tex] it seems natural to conclude that the magnitude of the buoyancy force is [tex](1.28 \cdot V_b + 0.18 \cdot \frac{4}{3} \cdot \pi \cdot R^3) \cdot g,[/tex] but this does not seem to provide the correct answer. Any advice?

Thank you for your time. :)
 
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  • #2
TMO said:
[tex] F_b = \rho_{fluid} \cdot V \cdot g [/tex]

This is the correct equation for the buoyant force. But you need to be careful about what density to use.

First think of a simple example, like a solid object immersed in water. Would the buoyant force be calculated using the density of the object, or the water?
 

1. What makes a helium balloon float?

A helium balloon floats because the gas inside it is lighter than the surrounding air. Helium is a gas that has a lower density than air, which causes it to rise and create buoyancy.

2. How does buoyancy affect a helium balloon?

Buoyancy is the upward force that a fluid (in this case, air) exerts on an object. In the case of a helium balloon, the buoyant force is greater than the weight of the balloon, causing it to rise.

3. Why does a helium balloon eventually deflate?

Over time, the helium gas inside the balloon will leak out through the tiny pores in the balloon's material. As the gas escapes, the balloon becomes heavier and eventually the weight of the balloon will be greater than the buoyant force, causing it to deflate and fall to the ground.

4. How does the size of a helium balloon affect its buoyancy?

The size of a helium balloon directly affects its buoyancy. The larger the balloon, the more helium gas it can hold, and therefore the greater the buoyant force will be. This is why larger balloons can lift heavier objects or stay afloat longer than smaller balloons.

5. Can other gases be used in place of helium for a balloon to float?

Yes, other gases such as hydrogen and hot air can also create buoyancy and allow a balloon to float. However, helium is typically used because it is non-toxic and non-flammable, making it safer for use in balloons.

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