- #1
Karajovic
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Homework Statement
A hang-glider, diving at an angle of 57.0o with the vertical, drops a water balloon at an altitude of 680.0 m. The water balloon hits the ground 5.20 s after being released.
a. What was the velocity of the hang-glider?
Homework Equations
The Attempt at a Solution
we know that the initial speed of the water balloon is the speed of the hang-glider... so:
∆y = vi(∆t)sinx - 1/2g∆t^2
680 = vi(5.2)sin57 - 1/2(-9.81)(5.2)^2
vi = 186 m/s
but my textbook says the answer is 193 m/s.
Is the book wrong? or am I wrong?
thanks!