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meaning of Square of four vector potential

 
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Mar8-13, 03:08 PM   #1
 

meaning of Square of four vector potential


The square of the four vector potential.

[itex](\phi,A)^2=\phi ^2 - A^2[/itex]

What's the physical meaning of this lorentz invariant?
 
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Mar8-13, 08:49 PM   #2
 
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If the invariant is timelike then it would be the scalar potential in a frame where the vector position was 0, and if the invariant is spacelike then it would be the magnitude of the vector potential in a frame where the scalar potential is 0. However, unless you are using the Lorentz gauge your gauge condition is frame variant so interpreting it becomes a little strange.
 
Mar16-13, 06:06 AM   #3
 
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hi merrypark3!

you can add any constant vector to the potential without changing the physics …

so you can make that invariant anything you like!
 
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