## Vector Identity (del operator)

i am completely lost as to how to go from
$$p^ \frac{1}{m}∇p$$
to
$$\frac{m}{m+1} ∇p^\frac{m+1}{m}$$
 In general, the chain rule should tell you that, $$\nabla p^a = a p^{a-1} \nabla p$$ Choose an appropriate value for $a$ and see what happens.
 oh wow.....nice trick