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Capacitor Diagram Transormations

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dwn
#1
Mar30-14, 05:28 PM
P: 127
I am having a difficult time understanding how they're transforming this capacitor schematic...what exactly is going on here? The example states that each cap is 7pF and the final answer C(eq) = 4.308pF....but why?
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NascentOxygen
#2
Mar31-14, 09:56 AM
HW Helper
Thanks
P: 5,328
There should be 3 figures to illustrate what the dialogue is describing, The first figure would be identical to that in your image #2. Then the Y network at its centre is transformed to Δ, producing the figure you have as image #1.

Finally, to consolidate the topic, they set you an exercise to apply what you have learnt, and this exercise is centred around your image #2.

You'll need the formulae for these impedance transformations, presumably your lectures have covered the topic? http://www.allaboutcircuits.com/vol_1/chpt_10/13.html


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