- #1
Demianu27
- 3
- 0
alright, I'm having trouble finding a formula to answer this problem.
a 58N weight is being suspended by 2 cables. the cable on the left side is horizontal, while the other cable is at a 60' angle.
What is the tension of the right side cable? (T1)
What is the tension of the left side cable, the horizontal one? (T2)
I started off by trying to find the sum of all the forces, but I'm already stuck.
I have;
{Fx = T2 - T1cos60 = 0
and
{Fy = T1sin60 - 58N = 0
is this right so far, or do i have the cos and the sin switched?
a 58N weight is being suspended by 2 cables. the cable on the left side is horizontal, while the other cable is at a 60' angle.
What is the tension of the right side cable? (T1)
What is the tension of the left side cable, the horizontal one? (T2)
I started off by trying to find the sum of all the forces, but I'm already stuck.
I have;
{Fx = T2 - T1cos60 = 0
and
{Fy = T1sin60 - 58N = 0
is this right so far, or do i have the cos and the sin switched?