New Reply

Bohr model of the atom

 
Share Thread
Mar6-12, 11:33 AM   #1
 

Bohr model of the atom


Eisberg and Resnick says that the condition for stability of the atom is:

k Ze2/r2=mv2/r

What I fail to understand is why the Z isnt square too. I mean surely you have Z electrons interacting with Z protons which which would surely give q1q2=(Ze)(-Ze)=-Z2e2?

What am I missing?
PhysOrg.com physics news on PhysOrg.com

>> Is there an invisible tug-of-war behind bad hearts and power outages?
>> Penetrating the quantum nature of magnetism
>> Rethinking the universe: Groundbreaking theory proposed in 1997 suggests a 'multiverse'
Mar6-12, 03:34 PM   #2
 
No. They are dealing with a one electron atom. You might say: then it's hydrogen, so why not put Z = 1? They leave Z open so the same treatment will do for, an He+ ion and so on.

Incidentally the equation you give isn't really the condition for stability. It is the classical F = ma equation for circular orbits. The stability condition is Bohr's condition: mvr = n[itex]\hbar[/itex].
New Reply

Similar discussions for: Bohr model of the atom
Thread Forum Replies
Bohr's model of the atom Introductory Physics Homework 0
Bohr model of atom Introductory Physics Homework 5
Bohr model atom problems involving allowed Bohr radii, energies, and energy levels. Introductory Physics Homework 4
Bohr model of atom... Introductory Physics Homework 6
the Bohr model of the H atom for anyone who needs it Chemistry 5