- #1
cowgiljl
- 63
- 1
A proton traveling at 3E6 m/s enters a region where the electric field has a magnitude of 3E5 N/C. The electric field is uniform and slows the proton's motions.
a)calculate the distamce the proton will travel before coming to a momentary halt?
B)Calculate the decel. of the proton and the time for it to trqavel this distance
F=qE = 1.6E-19 * 3E5 = 4.8E-14 N
a = F/m 4.8E-14 / 1.67E-31 a = 2.87E13 m/s
D = Vf^2 - Vi^2 / 2A = 3E6^2 / 2 * 2.87E13 = .157 m
I am not sure how to do part B or what formula to use
thanks joe
a)calculate the distamce the proton will travel before coming to a momentary halt?
B)Calculate the decel. of the proton and the time for it to trqavel this distance
F=qE = 1.6E-19 * 3E5 = 4.8E-14 N
a = F/m 4.8E-14 / 1.67E-31 a = 2.87E13 m/s
D = Vf^2 - Vi^2 / 2A = 3E6^2 / 2 * 2.87E13 = .157 m
I am not sure how to do part B or what formula to use
thanks joe