That should be (F/A)/(ΔL/L).joseg707 said:Homework Equations
Elastic Modulus=F/A/L/[tex]\Delta[/tex]L
Area = pi*r². Looks like you have an extra factor of two in there. And ΔL/L = 0.002.joseg707 said:6.28N/(2[tex]\pi[/tex]1x10-8/.02=5x109N/m2
The elastic modulus of a wire is a measure of its stiffness or ability to resist deformation. It is defined as the ratio of stress (force per unit area) to strain (change in length per unit length) in a material.
The elastic modulus of a wire can be determined through various experimental methods such as tensile testing, where the wire is stretched until it reaches its breaking point. The stress-strain curve generated from this test can be used to calculate the elastic modulus.
The elastic modulus of a wire is affected by several factors including the material it is made of, its composition and structure, temperature, and any external forces or stresses applied to it.
The elastic modulus is important in wire applications because it determines the wire's ability to withstand bending, stretching, and other mechanical stresses without permanently deforming. It also affects the wire's ability to transmit electrical signals.
The elastic modulus can vary greatly for different types of wire depending on their material composition and structure. For example, steel wires have a higher elastic modulus than copper wires, making them more suitable for applications that require high stiffness.