about lighting strikes and sources


by bottecchia
Tags: lighting, sources, strikes
bottecchia
bottecchia is offline
#1
Nov29-13, 10:47 AM
P: 3
Hello everyone.

I would like to know why we simulate in programs like atp lighting strikes with current sources and not with voltage sources.

Could anyone help?

Thank you :)
Phys.Org News Partner Engineering news on Phys.org
SensaBubble: It's a bubble, but not as we know it (w/ video)
WSU innovation improves drowsy driver detection
Faster computation of electromagnetic interference on an electronic circuit board
mfb
mfb is offline
#2
Nov29-13, 11:31 AM
Mentor
P: 10,853
No idea about lightning strike simulations, but from the electrics side:
If you put a small resistor (whatever gets hit by lightning) in series with a large resistor (all the air) and attach it to a voltage source (cloud-ground), the current through the resistors doesn't depend significantly on the resistance value, but voltage does.
bottecchia
bottecchia is offline
#3
Nov29-13, 11:58 AM
P: 3
so why we cannot simulate the lightning strike with a voltage source?

we will have a small resistance and a high voltage so we will produce a high current between the cloud and the ground.

does anyone know what is wrong in my thoughts?

nsaspook
nsaspook is offline
#4
Nov29-13, 12:37 PM
P: 498

about lighting strikes and sources


Quote Quote by bottecchia View Post
so why we cannot simulate the lightning strike with a voltage source?

we will have a small resistance and a high voltage so we will produce a high current between the cloud and the ground.

does anyone know what is wrong in my thoughts?
It's represented by the equivalent of a current source because once we exceed the breakdown voltage of air to the grounding point the measured current is almost equal to the short circuit current for a wide range of path resistances (a high impedance source). The impedance of the object in the path of current flow determines the amount of voltage generated across that object as the voltage will rise to the level needed to maintain constant current.
bottecchia
bottecchia is offline
#5
Nov29-13, 03:40 PM
P: 3
Quote Quote by nsaspook View Post
It's represented by the equivalent of a current source because once we exceed the breakdown voltage of air to the grounding point the measured current is almost equal to the short circuit current for a wide range of path resistances (a high impedance source). The impedance of the object in the path of current flow determines the amount of voltage generated across that object as the voltage will rise to the level needed to maintain constant current.
wow..... thank you man you are my hero... :)
mitre
mitre is offline
#6
Dec2-13, 12:51 PM
P: 1
Could you be more specific?

Quote Quote by nsaspook View Post
It's represented by the equivalent of a current source because once we exceed the breakdown voltage of air to the grounding point the measured current is almost equal to the short circuit current for a wide range of path resistances (a high impedance source). The impedance of the object in the path of current flow determines the amount of voltage generated across that object as the voltage will rise to the level needed to maintain constant current.
nsaspook
nsaspook is offline
#7
Dec3-13, 10:43 PM
P: 498
Quote Quote by mitre View Post
Could you be more specific?
This mighty help.
http://www.dehn-usa.com/manager/file...Img&idValue=38
davenn
davenn is offline
#8
Dec3-13, 10:57 PM
Sci Advisor
PF Gold
davenn's Avatar
P: 2,245
thanks nsaspook

nice informative link

Dave


Register to reply

Related Discussions
Generators - Voltage Sources or Current Sources? Electrical Engineering 7
Lighting strikes Classical Physics 21
Lighting a candle, blowing it out and relighting it by lighting the smoke? General Physics 3
Why are most electrical sources, voltage sources? Electrical Engineering 4
The lighting. Forum Feedback & Announcements 5