Calculating Micrometer Reading Change for 50 Fringes at λ = 550 nm

[Benzoate]

Homework Statement

Suppose the calibration constant of your spectrometer is 0.5, and suppose the wavelength of the light is λ = 550 nm. How much does the micrometer reading change during the movement of M2 that generates the passage of 50 fringes?

Homework Equations

possibly delta(l)= delta(n)*lambda /2
delta(m)= delta(l)/K , K being some constant to find the distance

The Attempt at a Solution

possibly delta(l)=50* 550 nm/ 2 delta(m)= delta(l)/K = 13750 nm/(.5) =27500 nm

 

[lylos]

Homework Statement

Suppose the calibration constant of your spectrometer is 0.5, and suppose the wavelength of the light is λ = 550 nm. How much does the micrometer reading change during the movement of M2 that generates the passage of 50 fringes?

Homework Equations

possibly delta(l)= delta(n)*lambda /2
delta(m)= delta(l)/K , K being some constant to find the distance

The Attempt at a Solution

possibly delta(l)=50* 550 nm/ 2 delta(m)= delta(l)/K = 13750 nm/(.5) =27500 nm

Is this from Modern Physics for Engineers? I have seen this problem before. When I get home in about an hour or two I'll try to digg up the answer.

 

[m2003]

Thank you for your question. Based on the information given, it seems that you are trying to calculate the change in micrometer reading for the movement of M2 that generates 50 fringes at a wavelength of 550 nm. To do this, you can use the equation delta(l) = delta(n)*lambda/2, where delta(l) is the change in micrometer reading, delta(n) is the number of fringes, and lambda is the wavelength of the light.

In this case, delta(n) = 50 and lambda = 550 nm, so delta(l) = 50 * 550 nm / 2 = 13750 nm. This is the change in micrometer reading that corresponds to 50 fringes at a wavelength of 550 nm.

However, it is also mentioned that the spectrometer has a calibration constant of 0.5. This means that the micrometer reading needs to be divided by this constant to get the actual distance in micrometers. So, the final answer would be delta(l) = 13750 nm / 0.5 = 27500 nm, which is the change in micrometer reading for the movement of M2 that generates 50 fringes.

I hope this helps. If you have any further questions, please let me know. Keep up the good work in your studies!