Calculating Acceleration of a Space Shuttle in Zero-Gravity Conditions

In summary: I really appreciate it. In summary, the space shuttle weighs 2.0 X 10^7 N on the surface of the earth, and when its engines provide a thrust of 2.4 X 10^7 N in space, the net force is 1.76 X 10^8 N m/s^2. Using the equation F=ma, the acceleration of the shuttle can be calculated to be 12 m/s^2.
  • #1
get_rekd
39
0
When the space shuttle is flying in space, away from the influence of any gravitational fields, its engines provide a total thrust of 2.4 X 10^7 N. If the shuttle weighs 2.0 X 10^7 N on the surface of the earth, what is its acceleration? (use g=10 m/s^2)

Fg= (2.0 X 10^7 N)(10 m/s^2)
= 2.0 X 10^8 N m/s^2

Fnet= (2.0 X 10^8 N m/s^2)-(2.4 X 10^7 N)
= 1.76 X 10^8 N m/s^2

a= 1.76 X 10^8

I have absolutely no clue how to do this but this is what I have figured out can someone please explain for me?
 
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  • #2
If the shuttle WEIGHS 2 x 10^7 N on earth, then this is the force.

What you need to calculate is the mass of the shuttle using F = mg

The question states that it is away from the influence of any gravitational fields, so the net force is given by the thrust.

Using F = ma you can then determine the acceleration.
 
  • #3
I'm sorry but I still don't understand.

so the mass of the shuttle would be 2 x 10^8 N then?
and Fnet= 2.4 X10^7?
 
  • #4
hey, lol this looks awefully similar to a problem i have in my textbook.. but anyway
its like how he said, u have to remember that mass doesn't change, weight does. So in earth, you are given a weight. Therefore, you can find the mass of the shuttle. you see

W=mg (use 10 for your g), then once you have that..use F(thrust)= ma

simple heh
 
  • #5
mass of the shuttle is in KG, and force is in NEWTONS (N), it is important to get the units right..
 
  • #6
OK... If something weighs 2 x 10^7 N, then this is the force with which gravity is pulling it towards Earth.

Its mass can be determined from a rearrangement of F= mg (mass is measured in kg)

Now, if we have a mass shooting through space, being pushed by an engine with a force of 2.4 x 10^7 N, we can figure out its acceleration using a rearrangement of F = ma.


Note that these are two different cases, so the F in each is different.
 
  • #7
right, use W=mg, because well its not wrong technically, but weight is a force, and in physics you generally use W for weight instead of Fg. anyway tell me what u get
 
  • #8
and remember the mass doesn't change
 
  • #9
I think my head is all goofed up today I just can't seem to do math correctly haa..

So I would then take,
2.4 X 10^7 N = (2.0 X 10^8 N)(a)
-2.0 X 10^8 N -2.0 X 10^8 N
-1.76 X 10^8 N = a??
 
  • #10
lol, atleast you realized that is wrong.. but look acceleration is (m/s^2) force is (kg m/s^2) aka: mass x acceleration. anyway lol
2.0x10^7 N= mg (10=g)
then take that mass
2.4x10^7N=ma (a is what you solving for) if i do anything more, i will end up solving the problem
 
  • #11
Not quite.

Your 2.0 x 10^8 is wrong.

W = mg

2.0 x 10^7 = m (10)

m=?

then use F(thrust) = ma
 
  • #12
okay so then...
2.0 X 10^7 = m(10)
-10 -10
1.9 X 10^7 = m

2.4 X 10^7 N = 1.9 X 10^7(a)
-1.9X10^7N -1.9X10^7N

5.0 X 10^6 N = a
 
  • #13
You are subtracting where you need to divide. - do the calculations again.

Other than that it looks ok.

Also, remember your units! acceleration is measured in m/s^2
 
  • #14
LOL! sorry, not to be mean, but that was funny
 
  • #15
alright so. For the 8th try haha! 2.4 X 10^7 N = 1.9 X 10^7 N a
then I divide 2.4 X 10^7 N by 1.9 X 10 ^7 N and get a
so a = 1.3 m/s^2
 
  • #16
nope.. i don't know what to say lol,
 
  • #17
okay so then...
2.0 X 10^7 = m(10)
-10 -10 (ERROR)-- fix that
1.9 X 10^7 = m (fix that)

2.4 X 10^7 N = 1.9 X 10^7 (fix that) (a)
-1.9X10^7N -1.9X10^7N (DIVIDE not multiply) 6=2x3 --> 3=6/2 or 2=6/3 (6-3 doesn't = 2-3)

5.0 X 10^6 N = a
 
  • #18
Thanks a lot for the help guys. I appreciate it!
 
  • #19
alright I think I figured it out now I hope to the lord.

2.0 X 10^7 N = m(10)
------------ -------
10 10

m= 2.0 X 10^6 N

2.4 X 10^7N = 2.0 X 10^6 N a
------------- ---------------
2.0X10^6N 2.0X10^6N

a= 12 m/s^2
 
  • #20
good lol :)
 
  • #21
finally! thank you so much for your patience and your help guys.
 
  • #22
alright I think I figured it out now I hope to the lord.

2.0 X 10^7 N = m(10)
------------ -------
10 10

m= 2.0 X 10^6 N (should be Kg) just saying because if u are writing this problem down, i don't want you to get points off for that.

2.4 X 10^7N = 2.0 X 10^6 N a
------------- ---------------
2.0X10^6N 2.0X10^6N

a= 12 m/s^2
 
  • #23
okay thank you.
 

1. How is acceleration calculated in zero-gravity conditions?

Acceleration in zero-gravity conditions is calculated using the formula a=F/m, where a is the acceleration, F is the force applied, and m is the mass of the object.

2. What is the value of acceleration in zero-gravity conditions?

The value of acceleration in zero-gravity conditions is typically 0 m/s². This is because there is no force of gravity acting on the object, so there is no acceleration due to gravity.

3. How does the acceleration of a space shuttle change in zero-gravity conditions compared to Earth's gravity?

In zero-gravity conditions, the acceleration of a space shuttle remains constant at 0 m/s². On Earth, the acceleration due to gravity is 9.8 m/s², which means the space shuttle would experience a greater acceleration due to Earth's gravity.

4. Can the acceleration of a space shuttle be negative in zero-gravity conditions?

No, the acceleration of a space shuttle cannot be negative in zero-gravity conditions. Negative acceleration, also known as deceleration, occurs when an object is slowing down. In zero-gravity conditions, there is no force acting on the object to cause it to slow down.

5. How does the mass of the space shuttle affect its acceleration in zero-gravity conditions?

The mass of the space shuttle does not affect its acceleration in zero-gravity conditions. According to Newton's second law of motion, the acceleration of an object is directly proportional to the force applied and inversely proportional to the mass. In zero-gravity conditions, there is no force acting on the object, so the mass does not play a role in the acceleration.

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