- #1
badgerbadger
- 7
- 0
Let X be a continuous random variable with density function
f(x)= .5e^|x|
for x range R. Find EX and Var(x)
help please!
f(x)= .5e^|x|
for x range R. Find EX and Var(x)
help please!
The formula for the distribution function is f(x)=.5e^|x|.
To find the expected value, EX, of the distribution function f(x)=.5e^|x|, you need to integrate the function from -∞ to +∞ and multiply it by x. This can be written as ∫-∞+∞xf(x)dx.
Using the formula from question 2, the expected value (EX) for the distribution function f(x)=.5e^|x| is 0.
The variance (Var(x)) can be found by taking the integral of x^2f(x) from -∞ to +∞ and subtracting the square of the expected value (EX)^2. This can be written as ∫-∞+∞x^2f(x)dx - (EX)^2.
Using the formula from question 4, the variance (Var(x)) for the distribution function f(x)=.5e^|x| is 2.