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Which should I use to prove this? |
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| Nov23-12, 06:14 PM | #1 |
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Which should I use to prove this?
(∂s/∂P) at constant volume =1/T ×(∂u/∂T)at constant volume × (∂T/∂P) at constant volume
s(P,v) Tds= du +pdv h= u + pv h(P,v) u(P,v) or other formula? How am I going to choose ? Please guide Thank |
| Nov23-12, 09:01 PM | #2 |
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Of those 'formulae', only two are equations. One of those two involves h, not mentioned anywhere else. So that leaves Tds= du +pdv as the only candidate. What would the constant volume version of that equation look like? |
| Nov23-12, 10:29 PM | #3 |
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So ∂s=(∂s/∂p)dp + (∂s/∂v)dv Then h=u + pv , can be dh= du + Pdv + vdp This is all just dealing with mathematics , please teach me how to choose Do you mean why did I put constant volume there? It means by keeping volume constant then only differentiate. Thank |
| Nov23-12, 10:30 PM | #4 |
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Which should I use to prove this?BiP |
| Nov23-12, 10:35 PM | #5 |
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and turn it into an equation involving partial derivatives, v being constant. |
| Nov24-12, 12:00 AM | #6 |
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I only can get (∂s/∂P) at constant volume = (1/T)(∂h/∂P)constant volume -(v/T) |
| Nov24-12, 02:51 AM | #7 |
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| Nov24-12, 03:33 AM | #8 |
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Trial
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| Nov24-12, 03:35 AM | #9 |
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This first , only that second deriavative
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| Nov25-12, 09:35 PM | #10 |
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You need to follow BiP's advice and familurize yourself with the derivation and application of the Maxwell equations.
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