Crush pressure on an underwater vacuum tube

In summary, a 6" diameter carbon steel pipe with a wall thickness of 3/8" and a yield of 80,000 psi (API 5L Grade X-80) will get you to a little over 18,000 feet in the ocean.
  • #1
Dumb Idea
10
0
So... let's say I wanted to drop a pipe on the ocean floor with a 6" inner diameter... which has a pretty strong vacuum in it... what general size/material do you suppose that would require... assume it is miles long.

I guess you could keep the vacuum pipe inside of another pipe that does not have a vacuum.
 
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  • #2
Having a vacuum inside only adds one atmosphere of extra pressure, equal to another 10m of water depth.
Given the depth of water at the ocean flor, the vacuum isn't going to make much difference.
 
  • #3
Thanks for that!


So... average ocean floor is 2.5 miles. How big you got to make a thing, a quasi conventional thing... I mean I couldn't make it out of titanium, to have a 6" ID?
 
  • #4
Hi Dumb Idea. Welcome to the board.

To determine the adaquecy of a pipe under external pressure, the piping code (ASME B31.3) is generally applicable. That code points you to the ASME Boiler and Pressure Vessel code. If you have a copy of the ASME BPV Div 1, look under para UG-28 for "Thickness of Shells and Tubes under External Pressure". You should have a copy in your library.
 
  • #5
Dumb Idea said:
So... let's say I wanted to drop a pipe on the ocean floor with a 6" inner diameter... which has a pretty strong vacuum in it... what general size/material do you suppose that would require... assume it is miles long.

I guess you could keep the vacuum pipe inside of another pipe that does not have a vacuum.

A quick hand calc shows that a 6" diameter carbon steel pipe with a wall thickness of 3/8" and a yield of 80,000 psi (API 5L Grade X-80) will get you to a little over 18,000 feet in the ocean.

I'm assuming there is no load on the pipe. If there is, then that will affect the collapse resistance of the pipe.

CS
 
  • #6
I have no experience designing underwater piping, but a thought that came up to me was buckling.

According to Roark's Table 35, Case 19a "Thin Tube Under Uniform lateral External Pressure; Very Long Tube with Free Ends," the critical external pressure required to buckle the tube would be 1357 psi (Young's Modulus of 29000 ksi, Poisson's Ratio of 0.29). This equates to an approximate depth of about 3000 ft (930 m), far short of the previously stated depth.
 
  • #7
Mech_Engineer said:
I have no experience designing underwater piping, but a thought that came up to me was buckling.

According to Roark's Table 35, Case 19a "Thin Tube Under Uniform lateral External Pressure; Very Long Tube with Free Ends," the critical external pressure required to buckle the tube would be 1357 psi (Young's Modulus of 29000 ksi, Poisson's Ratio of 0.29). This equates to an approximate depth of about 3000 ft (930 m), far short of the previously stated depth.

That would be for a vertical pipe under its own self weight. The OP appears to be asking about the collapse pressure rating of a pipe laying on the seabed in 13,500 feet of water depth...so buckling shoudn't be a problem.

If it is vetical, then of course he'll have to consider buckling.

CS
 
  • #8
stewartcs said:
That would be for a vertical pipe under its own self weight. The OP appears to be asking about the collapse pressure rating of a pipe laying on the seabed in 13,500 feet of water depth...so buckling shoudn't be a problem.

If it is vetical, then of course he'll have to consider buckling.

CS

We are not talking about longitudinal buckling, we are talking about the circular cross-section of the pipe itself buckling. Since the tube would be evacuated (or at least have a very low internal pressure) I think the application is valid.
 
  • #9
Here is the calculation in MathCAD, in pdf form. According to the sheet, he may have to have 0.75 in wall thickness at 13,500 ft, but the sheet is not valid for thick walls so an FEA model may be in order, or another equation if it exists.
 

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  • #10
Mech_Engineer said:
Here is the calculation in MathCAD, in pdf form. According to the sheet, he may have to have 0.75 in wall thickness at 13,500 ft, but the sheet is not valid for thick walls so an FEA model may be in order, or another equation if it exists.

The first problem with your calculation is that the radius is not 6.75 inches. The outside diameter is 6.75 inches. Hence, use a radius of 3.375 inches instead. If you do that, your numbers work out to over 24,000 feet!

Secondly, you're not considering the yield strength of different materials. API 5C3 is a good reference for these types of caclulations. They have verified their formulas with emperical tests too.

BTW, as I was typing this I noticed I used 6-in as the OD instead of the ID, so the revised calc would be good for 14,000-ft with the original numbers instead of 18,000-ft.

CS
 
  • #11
Oops! Good catch on the radius/diameter error. Looks like buckling probably won't be a problem at the depths he is talking about. Unfotunately, the equation isn't valid for a .375 wall thickness and 3.375 radius, so the result isn't useful anyway.

stewartcs said:
Secondly, you're not considering the yield strength of different materials.

Yield strength isn't taken into account in a buckling calculation, only the Modulus of Elasticity and Poisson's ratio.
 
  • #12
Mech_Engineer said:
Oops! Good catch on the radius/diameter error. Looks like buckling probably won't be a problem at the depths he is talking about.

No problem, I do it all the time!

I always tend to think of it as the collapse resistance of the pipe instead of buckling. I don't like using the term buckling unless I deal with columns (or vertical pipe in the ocean)! :wink:

CS
 
  • #13
Mech_Engineer said:
Yield strength isn't taken into account in a buckling calculation, only the Modulus of Elasticity and Poisson's ratio.

That's why I don't think of it in terms of buckling. The yield strength definitely comes into play with collapse resistance of pipe in the ocean! Typically because they are vertical and in order to prevent them from buckling a tension must be applied at the top of the pipe. This results in a degraded or equivalent yield strength of the material which results in less of a collapse resistance.

CS
 
  • #14
Buckling, Elastic Stability, Crush Resistance, it's all the same to me :wink: Your explanation definitely makes sense though.
 

1. What is crush pressure on an underwater vacuum tube?

Crush pressure on an underwater vacuum tube is the amount of pressure that a vacuum tube can withstand before it collapses or breaks. This is an important factor to consider when designing and using vacuum tubes in underwater environments.

2. How is crush pressure measured on an underwater vacuum tube?

Crush pressure is typically measured in units of pressure, such as pounds per square inch (psi) or newtons per square meter (N/m²). It can also be measured in terms of depth, as the pressure increases with depth due to the weight of the water above.

3. What factors affect the crush pressure of an underwater vacuum tube?

The main factors that affect crush pressure on an underwater vacuum tube include the material and thickness of the tube, the depth of the water, and the external pressure applied to the tube. Other factors may include the temperature and chemical composition of the water.

4. What is the maximum crush pressure that an underwater vacuum tube can withstand?

The maximum crush pressure that an underwater vacuum tube can withstand depends on various factors such as the design and materials used. Some tubes can withstand pressures of up to thousands of psi, while others may only withstand a few hundred psi.

5. How do engineers ensure that an underwater vacuum tube can withstand crush pressure?

Engineers use various techniques such as stress analysis and simulations to design vacuum tubes that can withstand the expected crush pressure. They also conduct rigorous testing to verify the tube's strength and make any necessary improvements before it is used in actual underwater environments.

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