- #1
dsr39
- 14
- 0
This is more a qualitative question than a specific homework question, but a homework problem got me wondering about it.
I was solving the finite potential well.
[tex]V(r) = 0 \hspace{1cm} r \geq a[/tex]
[tex]V(r) = -V_0\hspace{1cm} r < a[/tex]
I am trying to solve for the ground state energy. When I find the forms of the solution in the interior of the well, I find that I get
[tex] \frac{c_1 \sin{(kr)} + c_2 \cos{(kr)}}{r} [/tex]
I know from doing other reading that I should end up throwing away the cosine term, but I do not understand why.
I can see that it blows up at [tex] r=0 [/tex], but it still looks like it will be normalizable to me since a volume integral in spherical coordinates provides an extra factor of [tex]r^2[/tex]
I was solving the finite potential well.
[tex]V(r) = 0 \hspace{1cm} r \geq a[/tex]
[tex]V(r) = -V_0\hspace{1cm} r < a[/tex]
I am trying to solve for the ground state energy. When I find the forms of the solution in the interior of the well, I find that I get
[tex] \frac{c_1 \sin{(kr)} + c_2 \cos{(kr)}}{r} [/tex]
I know from doing other reading that I should end up throwing away the cosine term, but I do not understand why.
I can see that it blows up at [tex] r=0 [/tex], but it still looks like it will be normalizable to me since a volume integral in spherical coordinates provides an extra factor of [tex]r^2[/tex]