- #1
dancer_smiley
- 6
- 0
Here is the problem: A chainsaw is started by pulling on a rope that is attached to a solid steel flywheel. Assume that the wheel has a mass of 1.5 kg that is completely distributed along the outside edge, and it has a diameter of 10 cm. It starts at rest and must accelerate to 4.0 rev/s in 2.0 seconds in order to start the motor. What torque must be applied to the flywheel?
Equation I used: Angular Acceleration = Torque/Moment of Inertia
Here is my attempt: (1.5 kg)(.05 m)^2 (4.0 rev/s / 2.0 s) = .0075
I don't think this is the correct answer, but I have no idea how to solve this question...
Equation I used: Angular Acceleration = Torque/Moment of Inertia
Here is my attempt: (1.5 kg)(.05 m)^2 (4.0 rev/s / 2.0 s) = .0075
I don't think this is the correct answer, but I have no idea how to solve this question...