Calculating Gravity Inside Complex Spherical Bodies

In summary, the conversation discusses the shell theorem and its application to different shapes and distributions of mass. It is clarified that the shell theorem does not apply to ellipsoids or disks and further discussion is had about the gravitational forces on a mass element placed between a spherical mass and a round plate or an infinite plate.
  • #1
dougettinger
26
1
I know about the shell theorem and that the force of gravity due to the mass of the shell is zero inside a spherical shell. I have some questions that may easily be answered.

1. Does this same conclusion hold for an ellipsoid and/or a disk with the shell on the exterior rim ?

2. How is the gravity force inside a spherical solid affected if it has two layers and a central core all with different but homogeneous densities ? Especially inside the middle layer that has the least density and least mass ?
 
Physics news on Phys.org
  • #2
dougettinger said:
1. Does this same conclusion hold for an ellipsoid and/or a disk with the shell on the exterior rim ?
No.
2. How is the gravity force inside a spherical solid affected if it has two layers and a central core all with different but homogeneous densities ? Especially inside the middle layer that has the least density and least mass ?
For a spherically symmetric mass distribution (even with varying densities), the gravitational field at any distance r from the center is only due to the mass within that radius--mass elements at distances greater than r do not contribute to the field at r.
 
  • #3
dougettinger said:
1. Does this same conclusion hold for an ellipsoid and/or a disk with the shell on the exterior rim ?
You can get that effect with any closed shape, but only in a sphere can the thickness of the walls be the same everywhere. A hollow ellipsoid for example needs to have thicker walls at the ends with the small radius of curvature. The part where the radius of curvature is large needs thinner walls. The exact thickness the walls need to have can be calculated in the same way as the electric charge distribution on a statically charged metal object.
 
  • #4
Thank you for your unexpected prompt replies. Let me clarify my problem. Let the mass element in question be between a massive sphere in the center and an outer massive shell which you could almost consider being flat with respect to the mass element, although it surrounds the massive sphere. I believe the shell theorem in this case has difficulties canceling the gravity forces of the shell due to the central mass.
Are Doc Al and DrZoidberg tags ?
 
  • #5
dougettinger said:
Let me clarify my problem. Let the mass element in question be between a massive sphere in the center and an outer massive shell which you could almost consider being flat with respect to the mass element, although it surrounds the massive sphere. I believe the shell theorem in this case has difficulties canceling the gravity forces of the shell due to the central mass.
You have a uniform spherical shell, right? So why would the shell theorem not apply, just like in any other case? How is the presence of the central mass relevant?
 
  • #6
Hello Doc Al,
The mass element is pulled in two directions; by the central mass and by an element of mass on the shell that cannot be canceled because it is interacting with the central mass.
The formalized shell theorem solution for a mass element inside a hollow sphere is always for the case of an empty sphere except for the mass element.

I am trying to be sure we both understand each other.
 
  • #7
dougettinger said:
Hello Doc Al,
The mass element is pulled in two directions; by the central mass and by an element of mass on the shell that cannot be canceled because it is interacting with the central mass.
The formalized shell theorem solution for a mass element inside a hollow sphere is always for the case of an empty sphere except for the mass element.

I am trying to be sure we both understand each other.
The shell theorem says: The spherical shell exerts no gravitational force on any mass element within the shell. Doesn't matter if it's empty or not.

In your example there will be a gravitational field within the shell, but that field is due to the central mass and not the shell.
 
  • #8
Doctor Al,
Thank you for being patient with me. Allow me to propose another example that does not utilize the shell theorem. Assume that the mass element in question is between a spherical mass and a round plate with a specified radius, density, and thickness. The mass element is on a line that is perpendicular to the plate and goes through the center of the spherical mass. The radius of the round plate compared to the radius of the sphere is much larger by a factor of 100. How are the gravity forces exerted on the mass element determined for such a case ?

Thoughtfully, Doug Ettinger
 
Last edited:
  • #9
dougettinger said:
Doctor Al,
Thank you for being patient with me. Allow me to propose another example that does not utilize the shell theorem. Assume that the mass element in question is between a spherical mass and an infinite plate with a specified density and thickness. The mass element is on a line that is perpendicular to the plate and goes through the center of the spherical mass. How are the gravity forces exerted on the mass element determined for such a case ?
Just add them up. Both the spherical mass and the infinite plate will exert a gravitational attraction on a mass element placed between them.

(Not sure how this relates to your original question.)
 

1. How does gravity work inside a solid sphere?

Gravity inside a solid sphere is determined by the mass of the sphere and the distance from the center of the sphere. The force of gravity is inversely proportional to the square of the distance from the center, meaning the closer you are to the center, the stronger the gravitational force.

2. Does the amount of gravity change as you move through a solid sphere?

Yes, the amount of gravity changes as you move through a solid sphere. As you move closer to the center of the sphere, the gravitational force increases due to the increased mass and decreased distance from the center.

3. How does the density of a solid sphere affect its gravitational pull?

The density of a solid sphere does not affect its gravitational pull. As long as the mass and distance from the center remain constant, the gravitational force will remain the same.

4. Can gravity exist inside a hollow sphere?

Yes, gravity can exist inside a hollow sphere. The gravitational force is still determined by the mass of the sphere and the distance from the center, regardless of whether the sphere is solid or hollow.

5. How does gravity inside a solid sphere compare to gravity on the surface of the sphere?

Gravity inside a solid sphere is stronger than gravity on the surface of the sphere. This is because the gravitational force is directly proportional to the mass of the sphere, and as you move closer to the center, the mass increases, resulting in a stronger gravitational force.

Similar threads

  • Other Physics Topics
Replies
1
Views
2K
  • Classical Physics
Replies
16
Views
837
Replies
5
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
547
Replies
1
Views
859
  • Introductory Physics Homework Help
Replies
16
Views
4K
Replies
17
Views
4K
  • Introductory Physics Homework Help
Replies
16
Views
6K
  • Introductory Physics Homework Help
Replies
11
Views
4K
  • Astronomy and Astrophysics
Replies
21
Views
1K
Back
Top