|Nov12-12, 07:52 PM||#1|
Differential Equation with growth
So, I have a differential equation with growth problem. It is a dm/dt function and I need to get it to dD/dt, change in diameter with time.
here is the original functon,
dm/dt= (pi/4)(D)^2* (V(D))*(LWC)*E
LWC = 2
V(D) = 343D^0.6 m/s
it starts from a diameter of 1mm and grows to 5mm and I need to find the time it takes.
I'm not asking for anyone to solve the problem and give me a final solution, but I need help in getting the dD/dt function.
I thought this was it.... but its not:
multiplying by dt ___ dm = [(pi/4)(D)^2 * (v) * (LWC) (E)] dt
integrating ___ m = [(pi/4)(D)^2 * (v) * (LWC) (E)] t
dividing ___ m / [(pi/4)(D)^2 * (v) * (LWC) (E)] = t
|Nov13-12, 07:53 AM||#2|
I don't see how you can possibly change from dm/dt to dD/dt without knowing how m is related to D.
|Nov13-12, 09:06 AM||#3|
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