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MichaelXY
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Homework Statement
This problem is giving me trouble on many levels.
Gold III hydroxide is used for electroplating gold onto other metals. It can be made from the reaction of KAuCl4 (aq) with sodium carbonate and water.
a. Write a balanced equation for this reaction.
b. To prepare a fresh supply of gold III hydroxide, a chemist makes 20.00g of the KAuCl4 with 25.00 g of the sodium carbonate. What is the percent yield if the actual amount of gold III hydroxide produced in the reaction is 10.56g?
Homework Equations
The Attempt at a Solution
Part (a) is my first difficult spot, I was able to come up with
NaCO3 + KAuCl4 + H2O -------> So I figure Au(OH)3 + KCL + CO3, before balancing
But the correct answer is:
3NaCO3 +2KAuCl4+3H20----> 2Au(OH)3 +2KCL+CO2 +6NACl
My first problem was that I do not see how we went from CO3 to CO2, second since CO3 and CO2 are polyatomics, how do we balance.
So I then went on to work the problem.
20 g KAuCl4 = .05292 moles
25 g NaCO3 = .301 mole
So since KAuCL4 is the smaller amount do I say that is the limiting factor? Assuming I am correct, I compute:
20 g KAuCl4 (1 mole KAUCl4/377.877g KAuCl4) (2 mole AuOH3/ 2 mole KAuCl4) (247.991 g AuOH3/ 1 mole AuOH3) = 13.125 g
So Actual over theo gives 80.45%
As any of that correct?
Thanks