by 215
Tags: confused, electromagnet
 P: 39 How do i calculate the magnet field for an Solenoid with an ironcore with x windings and y amps.. The same for an horseshoe magnet, where there is an air gap about 2mm.. For some reason does my calculation not make sense..
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P: 11,888
 Quote by 215 For some reason does my calculation not make sense..
It would be easier to look for a mistake if you added your calculations here.
 P: 39 ohh sorry my bad.. I have choosen to use 1A as constant. For the Horseshoe magnet B = $\frac{i*n*µ0*µr}{lj+2vµr+2xµr}$ lj = length of the ironcore = 0.034+0.011+0.034 µ0 = 4pi *10^-7 x= length of one of the airgaps v= length of the other airgap µr = Relative permability = µ0(1+XM)=5000 I = 1 For the solonoid B = µrH H=$\frac{N*I}{l}$ l = 0.065 I = 1 I know B = 0.4 I've been trying to solve for N, windings, and for the solonoid do i get 22, and for the horseshoe do i get 1688..
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P: 11,888